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kati45 [8]
3 years ago
14

What is standard notation?

Mathematics
1 answer:
Marizza181 [45]3 years ago
4 0
<span>Standard notation is when a number is completely written out using numerical digits

Hope it helps</span>
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Help me plzzzzzzzzzzz
Inga [223]

Answer:

A = 3

B = -5

C = 2

Step-by-step explanation:

The way to format a quadratic equation is: ax^2 + bx + c, so the first step to solving this is to format it in the right way, where the x^2 comes first, the x second, and the number alone.

After formatting, your equation should look like this: 3x^2 - 5x + 2

From here, you can see the the <em>a </em> is 3, the <em>b</em> is -5, and the <em>c </em>is 2

7 0
3 years ago
Brainiest if correct or first<br> 1/2(6x+1/2)
Alexxx [7]

Step-by-step explanation:

1/2(6x+1/2)=0

3x+1/4=0

3X=-1/4

X=3(-1/4)

X=-3/4

OR

X=-.75

8 0
3 years ago
Read 2 more answers
Antonia participated in a run-a-thon and raised $265 for her school. She received $25 in donations and an additional $8 for ever
SIZIF [17.4K]

Answer:

30

Step-by-step explanation:

5 0
3 years ago
In ΔRST, t = 4.1 inches, r = 7.1 inches and ∠S=45°. Find the length of s, to the nearest 10th of an inch.
dem82 [27]

Answer:

The length of s is 5.1 inches to the nearest tenth of an inch

Step-by-step explanation:

In Δ RST

∵ t is the opposite side to ∠T

∵ r is the opposite side to ∠R

∵ s is the opposite side to ∠S

→ To find s let us use the cosine rule

∴ s² = t² + r² - 2 × t × r × cos∠S

∵ t = 4.1 inches, r = 7.1 inches, and m∠S = 45°

→ Substitute them in the rule above

∴ s² = (4.1)² + (7.1)² - 2 × 4.1 × 7.1 × cos(45°)

∴ s² = 16.81 + 50.41 - 41.1677568

∴ s² = 26.0522432

→ Take √ for both sides

∴ s = 5.10413981

→ Round it to the nearest tenth

∴ s = 5.1 inches

∴ The length of s is 5.1 inches to the nearest tenth of an inch

3 0
3 years ago
Read 2 more answers
A population has a mean of 300 and a standard deviation of 40. Suppose a sample of size 100 is selected and is used to estimate
bazaltina [42]

Answer:

a: 0.9544 9 within 8 units)

b: 0.9940

Step-by-step explanation:

We have µ = 300 and σ = 40.  The sample size, n = 100.  

For the sample to be within 8 units of the population mean, we would have sample values of 292 and 308, so we want to find:

P(292 < x < 308).

We need to find the z-scores that correspond to these values using the given data.  See attached photo 1 for the calculation of these scores.

We have P(292 < x < 308) = 0.9544

Next we want the probability of the sample mean to be within 11 units of the population mean, so we want the values from 289 to 311.  We want to find

P(289 < x < 311)

We need to find the z-scores that correspond to these values.  See photo 2 for the calculation of these scores.

We have P(289 < x < 311) = 0.9940

5 0
3 years ago
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