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Xelga [282]
3 years ago
13

Johnathan plans on using 2" x 12" boards that cost $2.50 per foot. Assuming he can purchase the exact amount he needs, how much

will it cost to purchase the wood?
Mathematics
1 answer:
Kitty [74]3 years ago
7 0

Answer:

$35

Step-by-step explanation:

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What is 80 percent of 60. write and solve a proportion. thank you
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4 0
3 years ago
Read 2 more answers
A can is 7 inches high and has a radius of 2 inches,
Yuliya22 [10]

Answer:

87.92 cubic inches

Step-by-step explanation:

to find the volume of a cylinder the formula is V = \pir^{2}h

so first i squared 2

2x2= 4

i then multiplied 4 by the height (7)

4x7 = 28

then times 28 by pi (3.14)

28x 3.14 = 87.92

4 0
3 years ago
A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
sveta [45]

Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

8 0
3 years ago
You are saving money for a new phone. You must have at least $800 saved up in
NeX [460]

Let number of hours needed to work = x

Multiply number of hours by rate: 15x

Add what you already have saved:

15x + 215

This needs to equal at least 800:

The equation becomes:

15x + 215 >= 800

Solve for x:

15x + 215 >= 800

Subtract 215 from both sides

15x >= 585

Divide both sides by 15

X >= 39

They have to work at least 39 hours.

6 0
3 years ago
A store is having a sale where school supplies are 30% off their original price. A backpack is on sale for $11.20. What was the
Mrac [35]
To find the original price, you could use a variable to represent the original price in this equation;

Let p represent the original price

.70 × p=11.20

to solve this, we'd isolate the variable (p) 

p=11.20 ÷.70

p=16

The original price was $16
7 0
3 years ago
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