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3 years ago

7

A can is 7 inches high and has a radius of 2 inches,

1 answer:

Yuliya22 [10]3 years ago

4 0

Answer:

87.92 cubic inches

Step-by-step explanation:

to find the volume of a cylinder the formula is V = $\pi$ $r^{2}$ h

so first i squared 2

2x2= 4

i then multiplied 4 by the height (7)

4x7 = 28

then times 28 by pi (3.14)

28x 3.14 = 87.92

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Let $M$ be the least common multiple of $1, 2, \ldots, 20$. How many positive divisors does $M$ have

Veronika [31]

Consider the prime factorization of 20!.

$20! = 20 \times 19 \times 18 \times \cdots \times 3 \times 2 \times 1$

The LCM of 1, 2, ..., 20 must contain all the primes less than 20 in its factorization, so

$M = 2 \times 3 \times 5 \times 7 \times 11 \times 13 \times 17 \times 19 \times m$

where $m$ is some integer not divisible by any of these primes.

Compare the factorizations of the remaining divisors of 20!, and check off any whose factorizations are already contained in the product of primes above.

$4 = 2^2$ - missing a factor of 2

$6 = 2\times3$ - ✓

$8 = 2^3$ - missing a factor of 2²

$9 = 3^2$ - missing a factor of 3

$10 = 2\times5$ - ✓

$12 = 2^2\times3$ - missing a factor of 2

$14 = 2\times7$ - ✓

$15 = 3\times5$ - ✓

$16 = 2^4$ - missing a factor of 2³

$18 = 2\times3^2$ - missing a factor of 3

$20 = 2^2\times5$ - missing a factor of 2

From the divisors marked "missing", we add the necessary missing factors to the factorization of $M$ , so that

$M = 2 \times 3 \times 5 \times 7 \times 11 \times 13 \times 17 \times 19 \times 2^3 \times 3$

Then the LCM of 1, 2, 3, …, 20 is

$M = 2^4 \times 3^2 \times 5 \times7 \times 11 \times 13 \times17 \times 19$

$\implies \boxed{M = 232,792,560}$

3 0

2 years ago

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guajiro [1.7K]

Answer:

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3 years ago

47,57,66,74,81,87,92 what is the pattern

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The next numbers are
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3 years ago

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4 years ago

1. Tracy has a photo album with 5 pages. Each

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Answer:

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Step-by-step explanation:

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