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Elis [28]
3 years ago
13

Six times a number is at least four less than eight times the number. If x represents the number, which will help find the numbe

r? 6 x less than 8 x minus 4 6 x less-than-or-equal-to 8 x minus 4 6 x greater-than-or-equal-to 8 x minus 4 6 x greater-than 8 x minus 4
Mathematics
1 answer:
jeyben [28]3 years ago
5 0

Answer:

The inequation 6x ≥ 8x - 4 can be used to find the solution.

The solution is x ≤ 2

Step-by-step explanation:

If x represents the number then six times a number is the multiplication of x by 6, and four less than eight times the number can be written as: 8x -4

6x ≥ 8x - 4

Solving the inequation;

Subtracting 6x each side:

0 ≥ 8x - 6x -4

Summing 4 each side

4 ≥ 2x

Dividing by 2 each side

2 ≥ x

2 greater or equal than x is the same as:

x ≤ 2

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Fantom [35]

Answer:

The x-intercept is 2.

Step-by-step explanation:

2 \sqrt[3]{x - 10}  + 4 = 0

2 \sqrt[3]{x - 10}  =  - 4

\sqrt[3]{x - 10 }  =  - 2

x - 10 =  - 8

x = 2

3 0
2 years ago
11,11,11,12,12,13,14,14,15 find the median
makvit [3.9K]

the median out of the data set is.

<u><em>12.</em></u>

to find the median, you have to,

The median is also the number that is halfway into the set. To find the median, the data should be arranged in order from least to greatest. If there is an even number of items in the data set, then the median is found by taking the mean (average) of the two middle-most numbers.


6 0
3 years ago
Please help me please!<br> Also, please show your work image shown below in attachment
WINSTONCH [101]

Answer:

see below

Step-by-step explanation:

some of your answers that you currently have are wrong, I'll note those mistakes below

- when factoring (ie 5x+15) only factor out things that can divide both numbers into a whole number ratio

5x+15 = 5(x+3), not (x+3)(x+5)

ie  \frac{10x^2+20x}{x+2}

we see that 10x can divide the numerator in a whole number ratio

10x^2+20x = 10x(x+2), not (x+2)(x+10)

second mistake: the first binomial expansion is incorrect.

you have the expansion formula right, but you added terms wrong, go look at it again

3. x^2+3x+2/ x^2+5x+6

(x+1)(x+2)/(x+3)(x+2)

(x+1)/(x+3)

4. (x^2+6x+8)/(x^2-16)

(x+4)(x+2)/(x+4)(x-4)

(x+2)/(x-4)

5. we can't simplify that any more, x and y are different variables so therefore we cannot cross out stuff on numerator and denominator

6. (x^4y^6)^2

(x^4y^6)(x^4y^6) = x^8y^{12}

remember that (x^a)(x^b) = x^(a+b)

or remember that (x^a)^b = x^ab

6 0
3 years ago
The figure below is a rectangular box in which EFGH and ABCD are rectangles and BF is perpendicular to planes EFGH and ABCD. Use
vladimir1956 [14]

Answer:

Step-by-step explanation:

Given question is incomplete: Find the compete question in the attachment.

a). Skew lines neither the parallel lines nor they intersect each other.

Two pairs of skew lines are BF and EH, & CG and EF.

b). Since EFGH and ABCD are rectangular planes and BF and DH are perpendicular to them,so both will be the altitudes between the planes.

Therefore, BF and DH will pe parallel.

c). BD and DH are the diagonals of the planes parallel to each other.

Therefore, BD and DH will be parallel.

d). Since BD and plane EFG don't intersect each other, so the solution will be an empty set.

e). HG is perpendicular to DH. So,the planes BDH and FHG containing these lines will be perpendicular to each other.

4 0
3 years ago
Point x starts at -4 on a number line. Pint x then goes through a series of moves; +3 units, -2 units, +6 units and -5 units. Wh
UkoKoshka [18]
-2. All you’re doing is going from the number you start with and performing the opperations in the order they appear (-4+3-2+6-5=-2)
3 0
3 years ago
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