It's important that you use the correct symbol to indicate exponentiation.
<span>f(x) = 0.4(3)x f(x) = 3(0.5)x f(x) = 0.8(0.9)x f(x) = 0.9(5)−x should be written as:
</span><span>f(x) = 0.4(3)^x f(x) = 3(0.5)^x f(x) = 0.8(0.9)^x f(x) = 0.9(5)−x.
Please double-check that last problem, as I am unsure of whether you meant 0.9^5 or (0.9)(5).
f(x) = 0.4(3)^x is definitely an exponential function.
Please try again. Do those problems that you can do an ask questions about the others.
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Answer:
That would be (2,3)
Step-by-step explanation:
When we're moving left in the coordinate plane, we are subtracting the x-coordinate by how much distance we move.
In this case, 7-5=2, so the new x-coordinate is 2, but the y-coordinate doesn't change since we're going horizontally and not vertically.
2 x 5/ 50 x 18
10 / 900
Divide both by 10
1/90
Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
Answer:
540°.
Step-by-step explanation:
On a unit circle, cos θ = -1 at 180°.
However, cos θ has a period of 2π, or 360°. This means that cos θ will equal to -1 again after 2π.
To solve for the angle:
180° + 360° = 540°. This is the next angle at which cos θ = -1.
