So all angles within a triangle should add up to 180, 102+31= 133 then subtract. 180-133=47
X-47
The question is about types and number of soultions so you must use b^2-4ac which is the experssion under the root in the quadratic formula
so
if
b^2-4ac=0 then there is one real soultion
if
b^2-4ac<0 then there are two imaginary soultions that differ in the sign between them
if
b^2-4ac>0 then there are two real soultions
so a polynomial is written in the form
ax^2+bx+c=0
so a=-4
b=-4
c=-1
so b^2-4ac=16-16=0
so one real soultion is the answer you are looking
type:real
number:1
Answer:
40+95 = 135
180-135 = 45 = 3rd interior i am not sure what the two exterior angles are
Step-by-step explanation:
180 is what we subtract 135 from because in all triangles all three angles should add up to 180.
Answer:abc about
Step-by-step explanation: all of them are bad
Answer:
-4/5
Step-by-step explanation:
Please use a symbol such as x or Ф to represent an angle; your 0 is too easily confused with zero.
If Angle Ф lies in the second quadrant, and sin Ф=3/5, find cos Ф.
The sine of an angle is the ratio of the length of the opposite side to the length of the hypotenuse: sin Ф = opp / hyp = 3 / 5. Thus the opp side has length 3 and the hyp has length 5. By the Pythagorean Theorem,
the adj side has length √(5² - 3²), or √(25-9), or √16, or ±4. Because the angle is in the 2nd quadrant, choose adj = -4.
Then the cosine of this angle is cos Ф = adj / hyp = -4 / 5
