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3 years ago

Need help with 13 and 14

Mathematics

1 answer:

ch4aika [34]3 years ago

7 0

13) 9 over 4 × 4 over 3
9 × 4 over 4 × 3
36 over 12 = 3 over 1
Therefore, your answer would be 3 over 1

14) 7 over 5 × 20 over 9
7 × 20 over 5 × 9
140 over 45 = 3 and 1 over 9
Therefore, your answer would have to be: 3 and 1 over 9.

:)

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600.000 rounded to the nearest ten thousand what Numbers would i be

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Answer:

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Step-by-step explanation:

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3 years ago

S y = -9 a solution of y + 1 = 8?

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Step-by-step explanation:

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3 years ago

How would I do the steps to solve this?

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Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

$R(p) = -10p^2+800p$

Taking derivative wrt p

$\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\$

Now putting R'(p) = 0

$-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40$

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

$R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000$

The maximum revenue is 16000 dollars (at p = 40)

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Step-by-step explanation:

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