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Feliz [49]
3 years ago
6

The path from Bart's house, H, to the library, L, forms a line segment. Maple Road, M, bisects this path. Bart's school, S, is t

he midpoint of the segment from Bart's house to Maple Road. The town hall, T, is the midpoint of the segment from Maple Road to the library. What landmark is the same distance from Bart's house as the school is from town hall? Draw a diagram to support your answer

Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0

The distance from the School to the Town hall is half the distance from Bart's house to the Library. Maple Road is the landmark that is half the distance from Bart's house to the library.

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F(x) =?. Vertex is (2,-4) the other given point is (1,-2)
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Given the vertex, (2, -4) as the minimum point, and that it is an upward-facing parabola that passes point (1, -2):

We could substitute these values into the vertex form of the quadratic function,

f(x) = a(x - h)^2 + k

where:

(h,k) is the vertex

The axis of symmetry is the vertical line x = 2

The value of “a” determines whether the graph opens up or down, and makes the parent function wider or narrower.

The value of “h” determines how far left or right the parent function is translated.

The value of “k” determines how far up or down the parent function is translated.


Now that we’ve established these definitions, we can substitute the given values into the vertex form:

f(x) = a(x - 2)^2 - 4

In order to determine the value of “a”, we must substitute the values of the other given point, (1, -2) into the equation:

f(x) = a(x - 2)^2 - 4

-2 = a(1 - 2)^2 - 4

-2 = a(-1)^2 - 4
-2 = a - 4

Add 4 to both sides to solve for “a”

-2 + 4 = a - 4 + 4
2 = a

Now that we have the value of a = 2, we can establish our quadratic function in vertex form:

f(x) = 2(x - 2)^2 - 4


I’m also including a screenshot of the graph of the function we came up with.


Please mark my answers as the Brainliest if you find my explanations helpful :)

5 0
3 years ago
Find the lengths of LM⎯⎯⎯⎯⎯⎯ and PQ⎯⎯⎯⎯⎯ and determine whether they are congruent.
Radda [10]

Answer:

5;5 and 65; they are congruent

8 0
3 years ago
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Tomtit [17]

Answer:

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3 years ago
A<br> Find tan a.<br> r<br> √5,-√7)<br> ✓[?<br> Enter
Virty [35]

Answer:

tan(\alpha)=-\frac{\sqrt{35}}{5}

Step-by-step explanation:

Tan can be defined as: \frac{sin(\theta)}{cos(\theta)} as it simplifies to opposite/adjacent. If you know a bit about the unit circle, you'll know that the x-coordinate is going to be cos(theta) and the y-coordinate is going to be sin(theta). Since the sin(theta) is defined as opposite/hypotenuse, and the hypotenuse = 1, so sin(theta) is defined as the opposite side, which is the y-axis. Same thing goes for cos(theta), except the adjacent side is the x-axis.

Using this we can define tan

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2 years ago
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The answer is c f(x)
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