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4 years ago

Using the figure below, what is the value of y?

Mathematics

1 answer:

Bess [88]4 years ago

6 0

Answer:

C. 132

Step-by-step explanation:

We assume all angle measures are in degrees. The vertical angles are equal in measure, so ...

4x = x +36

3x = 36

x = 12

x +36 = 48

y = 180 -48 = 132

The value of y is 132.

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3 years ago

(2,5) (7,9) (3,9) (5,8) is it a function

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3 years ago

Which equations are true? A. 10 × 10 × 10 × 10 × 10 = 50 B. 10 × 10 × 10 × 10 × 10 = 105 C. 10 × 10 × 10 × 10 × 10 = 10,000 D. 1

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3 years ago

Read 2 more answers

12 laps in 36 min how many in an hour

Ira Lisetskai [31]

First, do 36/12 to find out how many laps you can run in a certain amount of minutes. It is 1 laps per 3 minuted. Then, do 3 times 20 because 60 minutes is in an hour. Then, 1 times 20 is 20. 20 laps is the correct answer.

7 0

3 years ago

Read 2 more answers

A. Find the common factors of 12 and 20.

Alchen [17]

Answer:

a. Common factors of 12 and 20 = 2, 2

2. Highest common factor of 12 and 20 = 4

3 packs of workbooks and 5 packs of text books to be purchased.

Step-by-step explanation:

a.) To find the common factors of 12 and 20:

First of all, let us find the factors of 12 and 20

12 = 2 $\times$ 2 $\times$ 3

20 = 2 $\times$ 2 $\times$ 5

The common factors are underlined above i.e. 2, 2.

2. The highest common factor between 12 and 20 is 2 $\times$ 2 = 4

-------------------------------------------

Workbooks are in packs of 25

Textbooks are in pack of 15

The school needs exactly same number of workbooks and textbooks.

And we have to find such least number.

This least number can simply be calculated by finding the LCM (Least Common Multiple).

LCM of two numbers p and q is the minimum number which is completely divisible by both the numbers p and q.

Let us find LCM of 25 and 15 using factorization method:

15 = 3 $\times$ 5

25 = 5 $\times$ 5

The common part is considered only once:

So LCM = 3 $\times$ 5 $\times$ 5 = 75

Hence, number of packs of workbooks to be bought = $\frac{75}{25} = 3$

number of packs of textbooks to be bought = $\frac{75}{15} = 5$

So, the answer are:

a. Common factors of 12 and 20 = 2, 2

2. Highest common factor of 12 and 20 = 4

3 packs of workbooks and 5 packs of text books to be purchased.

8 0

4 years ago