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Roman55 [17]
3 years ago
5

What’s the answer???(SOMEONE PLEASE HELP)

Mathematics
1 answer:
Ket [755]3 years ago
6 0

we need the previous question

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THE ANSWER IS
TRIANGLE

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In the given figure, angle APC =<br>angle BQD. Prove that: AB //CD.<br>​
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• If<em> y(x)</em> = <em>e</em>², then <em>y</em> is constant and <em>y'</em> = 0. Then <em>y'</em> - <em>y</em> = -<em>e</em>² ≠ 0.

• If <em>y(x)</em> = <em>x</em>, then <em>y'</em> = 1, but <em>y'</em> - <em>y</em> = 1 - <em>x</em> ≠ 0.

The actual solution is easy to find, since this equation is separable.

<em>y'</em> - <em>y</em> = 0

d<em>y</em>/d<em>x</em> = <em>y</em>

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ln|<em>y</em>| = <em>x</em> + <em>C</em>

<em>y</em> = exp(<em>x</em> + <em>C </em>)

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8 0
3 years ago
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