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dlinn [17]
3 years ago
9

HELP ME FIND SLOPE RATE CHANGE WILL GIVE BRAINLIEST

Mathematics
1 answer:
il63 [147K]3 years ago
5 0

Answer:

1. RS= slope of 5/2

2. Pt= slope of -6/1 or -6

3.PQ= slope of 1/5

4. TS=slope of 0

5. QR= slope of -1/2

Step-by-step explanation:

Rise / run then simplify

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Please answer these last four questions.
Crank

Answer:

numbwer 8 is 44.04

Step-by-step explanation:

plz put brainliest

4 0
3 years ago
Ya'll how do I graph this? I haven't graphed anything in 3 years
Artyom0805 [142]

Answer:

I hope you get it .............

4 0
3 years ago
PLEASE I NEED HELP
notka56 [123]

You would transform 5x + 2x into the same term with the associative property, adding like terms. If you subsitute the different values into the expressions you notice that both have a rate of change of 7 like an arithmetic sequence. To see if any value will make the two expressions equal you make them equal to each other.

5x + 2x = 7x -1

7x = 7x - 1

0 = -1

No they will never have be a solution  to both expressions to make them equal because they're parallel to each other.

7 0
4 years ago
PLS HELP I NEED HELP
Vinvika [58]

Answer:

yo dont click that link hes a scammer thats an ip grabber

4 0
3 years ago
Find the numbers b such that the average value of f(x) = 7 + 10x − 9x2 on the interval [0, b] is equal to 8.
barxatty [35]

Answer:

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

Step-by-step explanation:

The mean value of function within a given interval is given by the following integral:

\bar f = \frac{1}{b-a}\cdot \int\limits^b_a {f(x)} \, dx

If f(x) = 7 +10\cdot x - 9\cdot x^{2}, a = 0, b = b and \bar f = 8, then:

\frac{1}{b}\cdot \int\limits^b_0 {7+10\cdot x -9\cdot x^{2}} \, dx = 8

\frac{7}{b}\int\limits^b_0 \, dx  + \frac{10}{b}  \int\limits^b_0 {x}\, dx - \frac{9}{b}  \int\limits^b_0 {x^{2}}\, dx = 8

\left(\frac{7}{b} \right)\cdot b + \left(\frac{10}{b} \right)\cdot \left(\frac{b^{2}}{2} \right)-\left(\frac{9}{b} \right)\cdot \left(\frac{b^{3}}{3} \right) = 8

7 + 5\cdot b - 3\cdot b^{2} = 8

3\cdot b^{2}-5\cdot b +1 = 0

The roots of this polynomial are determined by the Quadratic Formula:

b_{1} \approx 1.434 and b_{2} \approx 0.232.

The numbers b such that the average value of f(x) = 7 +10\cdot x - 9\cdot x^{2} on the interval [0, b] is equal to 8 are b_{1} \approx 1.434 and b_{2} \approx 0.232.

7 0
3 years ago
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