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3 years ago

50.5 is what percent of 40.4

Mathematics

2 answers:

9966 [12]3 years ago

8 0

20.2 is the perfect answer

s344n2d4d5 [400]3 years ago

5 0

50.5% of 40.4=20.402

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A right rectangular prism has these dimensions:

Andreyy89

I believe the volume would be 0.74^3

7 0

3 years ago

Find the measure of HIW in picture.

Contact [7]

10x+2x+13=145
angle of WIJ and HIW is equal to 145 degrees
12x+13=145
12x=132
x=11
angle of WIJ is 10x
angle of HIW is 2x+13
to find angle of HIW, you plug in x=11 into 2x+13 and
the answer and angle of HIW is 35 degrees.

6 0

3 years ago

What is the equation for the line? Enter your answer in the box.

Tema [17]

i think it is 2 and half

7 0

3 years ago

Read 2 more answers

-4+6y=16 Change to slope (intercept)

hichkok12 [17]

*here is step by step*
(Remember to add the 'x' to the slope)

-4x+6y=16

6y=4x+16

y= 4/6x + 2.66

The complete answer is:
y= 2/3x + 2.66

7 0

3 years ago

1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6

meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

2x-2y=-6

7x =-21

x= -3

Putting value of x in equation 1

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

$\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$

Let

$\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]$ = A $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = X and $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$ = B

Then AX= B

or X= A⁻¹ B

where A⁻¹= adj A/ ║A║ where mod A≠ 0

adj A= $\left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]$

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]$ $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}42\\0\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-3\\0\\\end{array}\right]$

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0

3 years ago