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snow_lady [41]
3 years ago
9

Suppose you are taking a multiple choice exam with 61 questions, each with 4 possible answers. If you were to guess at random fo

r each question, how many questions would you expect to get right
Mathematics
1 answer:
Brut [27]3 years ago
7 0

Answer:

15.25

Step-by-step explanation:

The probability of getting a question right is 1/4 because there are 4 possible answers, and you're just guessing randomly.

You can expect to get 1/4 of the questions right.

\frac{1}{4}\times 61 =15.25

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How can you do a picture using 2.8÷7
Margarita [4]
The answer to this question is 0.4

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3 years ago
Whats 834×5 plz tell me
amm1812
It is 4170 I believe if my calculations are correct
5 0
3 years ago
Read 2 more answers
Find constants a and b such that the function y = a sin(x) + b cos(x) satisfies the differential equation y'' + y' − 7y = sin(x)
Elza [17]
The first thing we must do in this case is find the derivatives:
 y = a sin (x) + b cos (x)
 y '= a cos (x) - b sin (x)
 y '' = -a sin (x) - b cos (x)
 Substituting the values:
 (-a sin (x) - b cos (x)) + (a cos (x) - b sin (x)) - 7 (a sin (x) + b cos (x)) = sin (x)
 We rewrite:
 (-a sin (x) - b cos (x)) + (a cos (x) - b sin (x)) - 7 (a sin (x) + b cos (x)) = sin (x)
 sin (x) * (- a-b-7a) + cos (x) * (- b + a-7b) = sin (x)
 sin (x) * (- b-8a) + cos (x) * (a-8b) = sin (x)
 From here we get the system:
 -b-8a = 1
 a-8b = 0
 Whose solution is:
 a = -8 / 65
 b = -1 / 65
 Answer:
 
constants a and b are:
 
a = -8 / 65
 
b = -1 / 65
4 0
3 years ago
Bonjour
solmaris [256]
<span>3 + t = 2 x t + 7    t =4 et x=0   vraie
</span><span>9 x (t-6) = 3 x t     t=4 et x=0    vraie
</span><span>4 x (t - 1) = t x t     t=2 st x=0    vraie

No, 25 cm c'est un 40 ou 41
No 23 cm c'est un 37



</span>
6 0
3 years ago
How to do the problem
marta [7]
There are 153 people who each ate 1/4 pounds. Therefore, the amount of watermelon eaten is 153/4 pounds.
The amount of watermelon served is
8 \frac{1}{4}  + 9 \frac{1}{4}  + 8 \frac{7}{8}  + 9 \frac{5}{8}  + 10 \frac{3}{4}
=  \frac{8 \times 4 + 1}{4}  +  \frac{9 \times 4 + 1}{4}  \\  +  \frac{8 \times 8 + 7}{8}  +  \frac{9 \times 8 + 5}{8} \\  +  \frac{10 \times 4 + 3}{4}
=  \frac{33}{4}  +  \frac{37}{4}  +  \frac{71}{8}  +  \frac{77}{8}  +  \frac{43}{4}  \\  =  \frac{33 \times 2}{4 \times 2}  +  \frac{37 \times 2}{4 \times 2}  +  \frac{71}{8}  \\  +  \frac{77}{8}  +  \frac{43 \times 2}{4 \times 2}
=  \frac{66 + 74 + 71 + 77 + 86}{8}
=  \frac{374}{8}  =  \frac{186}{4}
There is 186/4 total watermelon. Minus the 153/4 that was eaten,
\frac{186 - 153}{4}  =  \frac{33}{4}  = 8 \frac{1}{4}

The leftover watermelon is 8 & 1/4 pounds.
6 0
3 years ago
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