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vitfil [10]
3 years ago
7

What is the domain and range of f(x)=3x-1?

Mathematics
1 answer:
Alenkinab [10]3 years ago
7 0
Domain: x
Range: f(x) {or y}

An example of a point for this equation would be (1 ,2) where 1 would be the domain (or x) and the range (or y) would be 2. Hope this helps :)
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Is the following relation a function? Graph of x equals y squared, which results in a horizontal parabola centered on the x axis
Rus_ich [418]

It is not a function.

For any positive x this graph will give two different values y, and that is not allowed to happen for functions.

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Which number is bigger 3.345 , 3.35 , 3.3
Daniel [21]
3.3,3.35,3.345







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Jon borrows 5.50 from his friends to pay for snacks, and 12.75 from his sister to go the movies. How much does he need to repay
elena55 [62]

Answer:

18.25

Step-by-step explanation:

Add 5.50 and 12.75

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Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordl
Karo-lina-s [1.5K]

Full Question

Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordless, and the other six are corded phones. Suppose that these components are randomly allocated the numbers 1, 2, . . . , 18 to establish the order in which they will be serviced.

What is the probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced?

What is the probability that two phones of each type are among the first six serviced?

Answer:

a. 0.149

b. 0.182

Step-by-step explanation:

Given

Number of telephone= 18

Number of cellular= 6

Number of cordless = 6

Number of corded = 6

a.

There are 18C6 ways of choosing 6 phones

18C6 = 18564

From the Question, there are 3 types of telephone (cordless, Corded and cellular)

There are 3C2 ways of choosing 2 out of 3 types of television

3C2 = 3

There are 12C6 ways of choosing last 6 phones from just 2 types (2 types = 6 + 6 = 12)

12C6 = 924

There are 2 * 6C6 * 6C0 ways of choosing none from any of these two types of phones

2 * 6C6 * 6C0 = 2 * 1 * 1 = 2.

So, the probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced is

3 * (924 - 2) / 18564

= 3 * 922/18564

= 2766/18564

= 0.149

b)

There are 6C2 * 6C2 * 6C2 ways of choosing 2 cellular, 2 cordless, 2 corded phones

= (6C2)³

= 3375

So, the probability that two phones of each type are among the first six serviced is

= 3375/18564

= 0.182

5 0
3 years ago
How many times does 13 go into 80
Tcecarenko [31]
13 x 6 = 78 you cant multiply anymore so that's how many times it can go in 80.
6 0
3 years ago
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