Answer: price of a senior citizen ticket = $3.71
Let the price of a child ticket = $4.43
Step-by-step explanation:
Let the price of a senior citizen ticket = x
Let the price of a child ticket = y
On the first day of ticket sales the school sold 22 senior citizen tickets and 10 child tickets for a total of $126. This will be:
22x + 10y = 126 ............ i
The school took in $51 on the second day by selling 3 senior citizen tickets and 9 child tickets. This will be:
3x + 9y = 51 ........... ii
22x + 10y = 126 ............ i
3x + 9y = 51 ........... ii
Multiply equation i by 3
Multiply equation ii by 22
66x + 30y = 378 ....... iii
66x + 198y = 1122 ........ iv
Subtract iii from iv
168y = 744
y = 744/168
y = 4.43
Since 3x + 9y = 51
3x + 9(4.43) = 51
3x + 39.87 = 51
3x = 51 - 39.87
3x = 11.13
x = 11.13/3
x = 3.71
They can be 25hours and 10 minutes apart. <span>This is possible because the </span>International dateline is not a straight line<span>.
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The equation between the number of days remaining and number of hours is given as y= -5x+50.
<h3>How to illustrate the equation?</h3>
Let y be the number of days remaining and x be the no.of hours.
From the graph the slope of the line is given by m.
m=(y2 - y1)/(x2 - x1)
m=(30 - 40)/(4 - 2)
m= -10/2 = -5.
The above slope is in between points 2 and 4. As the line has a constant rate of growth the slope is the same between any points of the line.
Therefore the equation between the no.of days remaining and no.of hours is given by
y=mx +c.
y=-5x+c
Now to find the value of c. This can be determined by substituting the x and y values at a particular instant. For x=0,y=50. Therefore by these values, we get,
50= -5(0)+c
c=50.
Therefore the relation between the number of days remaining and number of hours is given as y= -5x+50.
Learn more about equations on:
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Step-by-step explanation:
4/9x-10>x/3-12
3 4/9x-3 10>x/3-12
4/3x-10>x-12
3 4/3x-3(10>x)-3(12)
4x-30x<-36
26x<-36
I don’t really no this answer? Sorry