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soldi70 [24.7K]
4 years ago
10

1: Explain Why (4,1) is not a solution to the equation y=3x+1

Mathematics
2 answers:
guapka [62]4 years ago
8 0
1. (4,1) is not a solution because when u sub it into the equation, it does not come out correct. It would be correct if it was (1,4).

2. C = 2.50d.....where C is the cost and d is the number of drinks bought. And if u pick any number for d, then u can solve for the cost (C).
Amiraneli [1.4K]4 years ago
8 0

Answer:

1. The point (4,1) is not a solution for the equation.

2. y=2.50x

Step-by-step explanation:

1. We are asked to explain why (4,1) is not a solution to the equation y=3x+1.

We can see that right side of equation would be greater than left side, when we will substitute coordinates of point (4,1).

Let us substitute coordinates of point (4,1) in our given equation as:

1=3(4)+1

1=12+1

1=13

Therefore, the point (4,1) is not a solution for the equation.

2. We have been given that drinks at the fair cost $2.50.

Let x represent number of drinks, so cost of x drinks would be 2.50x.

The total cost (y) of x drinks would be y=2.50x.

Therefore, the equation 2.50x represents the given equation.

Table:

Number of drinks                       Total cost

1                                                       $2.50

2                                                      $5.00

3                                                       $7.50

4                                                      $10.00

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Literally Infinity :P i dont know what number that would be
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Using pemdas please
Leni [432]

The expression that represents the amount mother spent is 4 × 5.00 + 2.00.

This outing will cost $22.00.

Solution:

Number of members in a family = 4

Cost of one ticket = $5.00

Cost of soft drink = $2.00

Mother spent = Number of members × Cost of each ticket + Cost of soft drink

                      = 4 × 5.00 + 2.00

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To solve this expression using PEDMAS rule.

First do multiplication.

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Now do addition.

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3 years ago
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Let F(x)=-7x-12 and g(x)=13-3x. What is f-g?
Oxana [17]

Answer:

(f - g)x = -4x - 25

Step-by-step explanation:

Given:

f(x) = -7x - 12

g(x) = 13 - 3x

Required:

(f - g)x

SOLUTION:

(f - g)x = f(x) - g(x)

f(x) - g(x) = (-7x - 12) - (13 - 3x)

= -7x - 12 - 13 + 3x

Collect like terms

= -7x + 3x - 12 - 13

(f - g)x = -4x - 25

8 0
4 years ago
BRAINLIEST! HELP! Please help me! I NEED PART D AND E! I’m so lost :(
Zinaida [17]

Part A

Given:

Volume of square pyramid = 73.5 <u>cubic</u> inches

height of square pyramid = 4.5 inches

To find:

1)Side length of square pyramid.

2)if side length of square pyramid is rational or irrational

Steps:

1) Side length = \sqrt{\frac{3v}{h} }

Side length = \sqrt{\frac{3*73.5}{4.5} }

Side length = \sqrt{\frac{3*73.5*10}{4.5*10} }         (multiplying both sides to make it a whole number)

Side length = \sqrt{\frac{3*735}{45} }

Side length = \sqrt{\frac{735}{15} }                  (3 gets canceled out)

Side length = \sqrt{49}

Side length = 7 inches

Therefore, the side length of the square pyramid is 7 inches long

2) 7 is a rational number, so the side length of the square pyramid is a rational number.

It is a rational number because,

it can be written in the form p/q,  where

1) q \neq0

2) p and q are co-prime

3) p and q are integers

Part B

Given:

Volume of Khafre's pyramid = 9/10 of Khufu's pyramid's volume

Volume of Kristina's first pyramid = 73.5 cubic inches

To find:

Volume of Kristina's second pyramid

Steps:

Volume of Kristina's second pyramid = 9/10 the volume of Kristina first pyramid

Volume of second pyramid = \frac{9}{10}*73.5

Volume of second pyramid = 9 * 7.35

Volume of second pyramid = 66.15 cubic inches

The volume of the second pyramid should be 66.15 cubic inches

Part C

Given:

Height of pyramid = 4.41 inches

Volume of pyramid = 66.15 cubic inches

To find:

1) Side length of pyramid

2) if the side length is rational or irrational

Steps:

1) Side length = \sqrt{\frac{3v}{h} }

Side length = \sqrt{\frac{3*66.15}{4.41} }

Side length = \sqrt{\frac{3*66.15*100}{4.41*100} }         (multiplying both sides to make it a whole number)

Side length = \sqrt{\frac{3*6615}{441} }

Side length = \sqrt{\frac{6615}{147} }                   (3 gets canceled)

Side length = \sqrt{45}

Side length of pyramid is \sqrt{45} inches

2) \sqrt{45} cant be written in the form of a fraction, so it is an irrational number

(if u want i can explain this more)

Part D

Given

Height of model pyramid = 4.5 inches

Height of Khufu's pyramid = 755.75 feet (had to search the internet for the answer, so I am not sure if it is correct)

Side length of model pyramid = 7 inches

Side length of Khufu's pyramid = 481.4 feet (had to search the internet for the answer)

To find:

1)If the model is to scale with Khufu's pyramid

2) If the model is close to scale with Khufu's pyramid

Steps:

1) First lets find the ratio of the height to the side length of the model

Ratio = 4.5 in : 7 in

         = 45 : 70

         = 9 : 14

         = 0.6428

Now lets find the ratio of the height to the side length of Khufu's pyramid

Ratio = 481.4 feet : 755.75 feet

         = 5776.8 in : 9069 in

         =  0.6369

Therefore the model is not to scale with Khufu's pyramid

2) Yes the scale is close

Part E

Given:

Height of model pyramid = 4.41 inches

Height of Khafre's pyramid = 448 feet

Side length of model pyramid = \sqrt{45} inches

Side length of Khafre's pyramid = 706 feet

To find:

1) If the model is to scale with Khafre's pyramid

2) If the model is close to scale with Khafre's pyramid

Steps:

1) First lets find the ratio of the height to the side length of the model pyramid,

Ratio = 4.41 in : \sqrt{45} in

= 4.41 : 6.7082

= 0.6574

Now lets find the ratio of the height to the side length of Khafre's pyramid

Ratio = 448 ft : 706 ft

= 5376 in : 8472 in

= 0.6345

Therefore the model is not to scale with Khafre's pyramid

2) No, the model is not close to scale,  (it depends by what is meant by close, for me its 0.01)

Happy to help, and I hope you learnt something from this answer that will help you in the future

If you didn't understand any topic pls ask

3 0
3 years ago
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