Its A!
if you plug 4 and -7, the equation works
Answer:
4.125 or 4 1/8 or 33/8
Step-by-step explanation:
Find the LCD and then combine.
Answer: 12 in. by 10 in.
Step-by-step explanation:
Given: The dimensions of photo is 10 in. by 8 in.
Therefore, Area of photo= 
Area of frame with photo=120 square inches
Let x be the width of the frame, then we have
Length of frame with photo= 10+2x inches
Width of frame with photo =8+2x inches
Now, 
![80+16x+20x+4x^2=120\\\Rightarrow\ 4x^2+36x-40=0\\\Rightarrowx^2+9x-10=0\\\(x-1)(x+10)=0\\\Rightarrow\ x=1,...........[text{Since length can not be negative so it cannot be -10}]](https://tex.z-dn.net/?f=80%2B16x%2B20x%2B4x%5E2%3D120%5C%5C%5CRightarrow%5C%204x%5E2%2B36x-40%3D0%5C%5C%5CRightarrowx%5E2%2B9x-10%3D0%5C%5C%5C%28x-1%29%28x%2B10%29%3D0%5C%5C%5CRightarrow%5C%20x%3D1%2C...........%5Btext%7BSince%20length%20can%20not%20be%20negative%20so%20it%20cannot%20be%20-10%7D%5D)
Thus, dimension of frame = 
I think it is 2/3y=9x+4, forgive me if im wrong
290:200
29:20
??? no hablo español bien.