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TEA [102]
4 years ago
12

What two numbers add to 15 and multiply to negative 312?

Mathematics
1 answer:
natima [27]4 years ago
6 0
X + y = 15
xy = -312

     x + y = 15
x - x + y = -x + 15
           y = -x + 15

                                           xy = -312
                               x(-x + 15) = -312
                           x(-x) + x(15) = -312
                                 -x² + 15x = -312
                       -x² + 15x + 312 = 0
           -1(x²) - 1(-15x) - 1(312) = 0
                    -1(x² - 15x + 312) = 0
                                  -1              -1
                          x² - 15x + 312 = 0
                          x = -(-15) ± √((-15)² - 4(1)(312))
                                                  2(1)
                          x = 15 ± √(225 - 1248)
                                               2
                          x = 15 ± √(-1023)
                                         2
                          x = 15 ± 31.984i
                                         2
                          x = 7.5 ± 15.992
                          x = 7.5 + 15.992    or    x = 7.5 - 15.992
                          x = 23.492        or         x = -8.492

              x + y = 15
     23.492 + y = 15
   - 23.492        - 23.492
                    y = -8.492
              (x, y) = (23.492, -8.492)

                      or

              x + y = 15
     -8.492 + y = 15
   + 8.492         + 8.492
                   y = 23.492
             (x, y) = (-8.492, 23.492)

The two numbers that add up to 15 and mutliply to -312 are -8.492 and 23.492.
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Sever21 [200]
Hello again!

We have this equation

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All we have to do is follow the steps that we know and remember, when you are doing Algebra make you used the easiest away. You can repeat the same steps over and over as long your answer is correct.

OMG I talked too much!

Ok let's solve this
 
x³ - 4x² + 2x + 10 = x² - 5x - 3
x³ - 4x² + 2x + 10 -x² -5x - 3 = 0
Now again, all we have to do is factorize. Be very careful when you are factorizing.

(x +1)(x² - 6x + 13) = 0
Set factors equal to 0
x + 1= 0 or x² - 6x + 13 = 0
x = -1
This is the answer!


Wait !


I didn't solve x² - 6x + 13 = 0 but I already know I will ended up having NO REAL SOLUTION!


I hope this help again!

A+ Guaranteed! Feel free to comment or message me if you have further questions about the answer.


Peace :)

 


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