Question

Which statement is true for the hang time of a projectile?

Answer 1

Answer:

It can be calculated solely by knowing the vertical component of the velocity of  projection.

Explanation:

As we know that two components of the velocity of projectile is given as

$v_x = vcos\theta$

$v_y = vsin\theta$

now the time of flight is the total time in which the total vertical displacement is zero is given as

$\Delta y = 0 = v_y t - \frac{1}{2}gt^2$

now we will have

$t = \frac{2v_y}{g}$

so we can find the time of flight just be finding the vertical component of the velocity so correct answer will be

It can be calculated solely by knowing the vertical component of the velocity of  projection.

Answer 2

It can be calculated solely by knowing the vertical component of the velocity of projection.

The amount of time a projectile stays in the air only depends on its movement in the vertical direction, which is dependent on the vertical component of its velocity.