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An object on the moon will weigh 1/6th of what it does on earth but have the same mass. Why is that?

elena55 [62]

Answer:

Because the weight depends of the gravity

Explanation:

This is because weight and mass are different, in order to better understand this problem we will apply an example with real values, which will help us to determine a person's weight.

A man has a mass of 80 [kg] on Earth when measuring his weight he realizes that it is 784.9 [N] and on the moon it is 130.8 [N]

On Earth

$g_{e} = 9.81[m/s^2]\\g_{m} = 1.635[m/s^2]$

Where:

g = gravity

Weight on the moon

Wm = 80 * 1.635

Wm = 130.8[N]

Weight on the earth

We = 80 * 9.81

We = 784.8[N]

In this way we can see that the weight depends on the gravity of where the person is located.

8 0

4 years ago

An alarm clock is dropped off the edge of a tall building. You, standing directly under it, hear a tone of 1350 Hz coming from t

frozen [14]

Answer:

the frequency clock would be 1262.85 Hz

Explanation:

Given data;

height of building h = 25 m

from the third equation of motion;

v² = u² + 2as

Since the Alarm clock falls with an acceleration equal to the acceleration due to gravity; a = g = 9.81 m/s²

initial velocity u = 0

so we substitute our values into the kinematic equation

v² = (0)² + 2 × 9.81 × 25

v² = 490.5

v = √490.5

v = 22.1472 m/s

Now, since the alarm clock is moving both I am stationary;

my velocity will be zero.

so Frequency of the alarm clock will be;

f' = [ (v - $v_{s}$ ) / ( v + $v_{0}$ ) ] × f

we know that; speed of sound is 343 m/s, so v = 343 m/s, $v_{s}$ is 22.1472 m/s, f is 1350 Hz, $v_{0}$ is 0 m/s

so we substitute the values into the equation

f' = [ (343 - 22.142 ) / ( 343 + 0 ) ] × 1350

f' = [ 320.858 / 343 ] × 1350

f' = 0.935446 × 1350

f' = 1262.85 Hz

Therefore, the frequency clock would be 1262.85 Hz

6 0

3 years ago

What does an alpha particle consist of?

antiseptic1488 [7]

The best answer to the question 'What does an alpha particle consist of?' would be letter c. An alpha particle consists of 2 protons and 2 neutrons. It is a particle that has no electrons and balances out the positively charged protons.

6 0

3 years ago

Read 2 more answers

The gas waste generated by many power plants is

lapo4ka [179]

carbon dioxide

is the answer

5 0

3 years ago

Read 2 more answers

The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed in toward the c

maria [59]

To solve this problem we will start using the concepts related to the electric field, from there we will find the load exerted on the body. Through this load it will be possible to make a sum of forces in balance to find the load that a human supports. Finally with these values it will be possible to find the repulsive force. We will proceed as follows,

The electric field is

$E= \frac{kQ}{R^2}$

Here,

k = Coulomb's Constant

Q = Charge

R = Distance (At this case from the center of mass of the earth to the surface)

Rearranging to find the charge,

$Q = \frac{ER^2}{k}$

Replacing,

$Q = frac{(150)(6.38*10^6)}{8.99*10^9}$

$Q = 6.79*10^5 C$

Since the electric field is directed towards the center of earth, the charge is negative.

PART A) Once the load is found we can proceed to apply the balance of Forces, for which the electrostatic force must be equivalent to the weight, this in order to satisfy the balance, therefore

$F_w = F_e$

$mg = \frac{kQq}{R^2}$

Replacing,

$(62)(9.8) = \frac{(8.99*10^9)(q)(-6.79*10^5)}{(6.38*10^6)^2}$

Solving for q,

$q = -4.056C$

PART B) Finally using the given distance and the values of the found load we can find the repulsive Force, which is

$F =\frac{kq^2}{d^2}$

$F = \frac{(8.99*10^9)(-4.056)^2}{110^2}$

$F = 1.22*10^7N$

PART C) The answer is no. According to the information found, we can conclude that traveling through an electric field is not viable because there is a repulsive force of great magnitude acting on the body.

3 0

3 years ago