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Why would an insurance company want people to avoid risk, like Nick Cannon having to avoid skydiving?

Lina20 [59]

An insurance company wants people to avoid risks because if the person meets with an accsident the expense of the medicines and treatment should be covered by the insurance company.

5 0

3 years ago

Read 2 more answers

When a tuning fork vibrates over an open pipe and the air in the pipe starts to vibrate, the vibrations in the tube are caused b

defon

Answer:

correct option is A. Resonance

Explanation:

solution

vibrations in the tube are caused by the Resonance because Resonance cause of sounds production in the musical instrument

As if resonance ( hollow cylindrical tube) immerse in cylinder of water and force in to vibration by tuning fork

As tines of tuning fork vibrate at natural frequency and it create sound wave that impinged up on opening of resonance tube

so correct option is A. Resonance

8 0

3 years ago

When light bulbs A and B are connected in series to a battery, A glows brightly and B glows dimly. You remove bulb B so that the

torisob [31]

Answer:

The bulb B glows brighter.

Explanation:

Given that,

A glows brightly and B glows dimly.

According to ohm's law,

Two light bulbs A and B are connected in series to a battery then the current will be same in both bulbs and the resistance is high of bulb A and low in bulb B.

If bulb A connect to a battery and bulb B connect to a same battery separately.

Then bulb B glows brighter because the resistance is high in bulb A so the current will be low.

The resistance is low in bulb B so the current will be high.

Hence, The bulb B glows brighter.

6 0

3 years ago

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A 11kg block slides up a 30° inclined plane at a constant velocity. The coefficient of friction between the block and the plane

astra-53 [7]

Answer:

The magnitude of the applied force is 94.74 N

Explanation:

Mass of the block, m = 11 kg

Angle of inclination of the plane, $\theta = 30^{\circ}$

Friction coefficient, $\mu_{k} = 0.2$

Now,

Normal force that acts on the block is given by:

$F_{N} = mgcos\theta + Fsin\theta$ (1)

Now, to maintain the equilibrium parallel to ramp the forces must be balanced.

Thus

$Fcos\theta = \mu_{k}F_{N}$ (2)

From eqn (1) and (2)

$Fcos\theta = \mu_{k}(mgcos\theta + Fsin\theta)$

$F(cos\theta - \mu_{k}sin\theta) = \mu_{k}mgcos\theta$

$F = \frac{\mu_{k}mgcos\theta}{cos\theta - \mu_{k}sin\theta}$

$F = \frac{0.2\times 11\times 9.8cos30^{\circ}}{cos30^{\circ} - 0.2\times sin30^{\circ}}$

F = 94.74 N

3 0

3 years ago

At a circus, a clown is being shot out of a cannon. This is a good thing because clowns are terrifying. The cannon's barrel make

nlexa [21]

Answer:

a) Please, see the attached figure.

b) The horizontal component of the initial velocity is 8.5 m/s

The vertical component of the initial velocity is 6.0 m/s

c) The clown will return to a height of 1.0 m after 1.2 s of the launch.

d) The clown will land safely on the mattress, 10.2 m from the cannon. If we include air resistance in the calculation, he will surely not reach the mattress because, without air resistance, he lands just 20 cm from the closest edge of the mattress.

Explanation:

Hi!

a) Please, see the attached figure.

b) As shown in the figure, the initial velocity vector is the following:

v0 = (v0x, v0y)

Using trigonomety of right triangles:

cos angle = adjacent side / hypotenuse

In this case:

Adjacent side = v0x

hypotenuse = v0

(see figure)

Then:

cos 35° = v0x / v0

v0 · cos 35° = v0x

v0x = 10.4 m/s · cos 35°

v0x = 8.5 m/s

The horizontal component of the initial velocity is 8.5 m/s

We proceed in the same way to find the vertical component:

sin angle = opposite side / hypotenuse

sin 35° = v0y / v0 (see figure to notice that opposite side = v0y)

v0 · sin 35° = v0y

10.4 m/s · sin 35° = v0y

v0y = 6.0 m/s

The vertical component of the initial velocity is 6.0 m/s

c) The equation of the position vector of the clown at time t is the following:

r = (x0 + v0 · t · cos α, y0 + v0 · t · sin α + 1/2 · g · t²)

Where:

x0 = initial horizontal position.

v0 = initial velocity.

t = time.

α = launching angle.

y0 = initial vertical position.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

We have to find the time at which the vertical component of the position vector is 1 m. Let´s place the origin of the system of reference at the point where the cannon is located on the ground so that x0 = 0 and y0 = 1.0 m.

Using the equation of the vertical component of the position:

y = y0 + v0 · t · sin α + 1/2 · g · t²

1.0 m = 1.0 m + 10.4 m/s · t · sin 35° - 1/2 · 9.8 m/s² · t²

0 = 10.4 m/s · t · sin 35° - 4.9 m/s² · t²

0 = t (10.4 m/s · sin 35° - 4.9 m/s² · t) (t = 0, when t = 0 the clown is 1.0 m above the ground, just leaving the cannon).

0 = 10.4 m/s · sin 35° - 4.9 m/s² · t

-10.4 m/s · sin 35° / -4.9 m/s² = t

t = 1.2 s

The clown will return to a height of 1.0 m after 1.2 s of the launch.

d) Now, let´s calculate the horizontal traveled distance after 1.2 s using the equation of the horizontal component of the position vector:

x = x0 + v0 · t · cos α (x0 = 0)

x = 10.4 m/s · 1.2 s · cos 35°

x = 10.2 m

Since the mattress is located at 10 m from the cannon and it is 2.0 m long, the clown will land safely on the mattress. However, the clown almost miss the mattress (he lands just 20 cm from the closest edge), so, if we include air resistance in the calculation, he will surely not reach the mattress.

6 0

4 years ago