Answer:
1) 64.2 mi/h
2) 3.31 seconds
3) 47.5 m
4) 5.26 seconds
Explanation:
t = Time taken = 2.5 s
u = Initial velocity = 0 m/s
v = Final velocity = 21.7 m/s
s = Displacement
a = Acceleration
1) Top speed = 28.7 m/s
1 mile = 1609.344 m
1 hour = 60×60 seconds
Top speed of the cheetah is 64.2 mi/h
Equation of motion
Acceleration of the cheetah is 8.68 m/s²
2)
It takes a cheetah 3.31 seconds to reach its top speed.
3)
It travels 47.5 m in that time
4) When s = 120 m
The time it takes the cheetah to reach a rabbit is 120 m is 5.26 seconds
Answer:
KE= 1/2 * mass * Velocity^2
Explanation:
1/2 * 72.0kg* 79^2 m/s = 224676 J
decomposing water does not require High activation energy
Answer:
Initial velocity, U = 28.73m/s
Explanation:
Given the following data;
Final velocity, V = 35m/s
Acceleration, a = 5m/s²
Distance, S = 40m
To find the initial velocity (U), we would use the third equation of motion.
V² = U² + 2aS
Where;
V represents the final velocity measured in meter per seconds.
U represents the initial velocity measured in meter per seconds.
a represents acceleration measured in meters per seconds square.
S represents the displacement measured in meters.
Substituting into the equation, we have;
35² = U + 2*5*40
1225 = U² + 400
U² = 1225 - 400
U² = 825
Taking the square root of both sides, we have;
Initial velocity, U = 28.73m/s
