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3 years ago

What is cocanve mirror?

Physics

2 answers:

pochemuha3 years ago

8 0

Answer:

A mirror that has a reflecting surface that is recessed inward is called concave mirror

professor190 [17]3 years ago

4 0

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and oh dusra a ohh o's ne answer kita ci prr o's ton baad hor vi answer kite h.oe ne osne

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Use the information and diagram to answer the following question.

Mumz [18]

Answer:b

Explanation:

Because I don’t know

8 0

3 years ago

The latent heat of fusion for Aluminium is 3.97 x 105. How much energy would be required to melt 0.75 kg of it?

RoseWind [281]

Answer:

$E = 2.9775\times10^5 J$

Explanation:

Given: The latent heat of fusion for Aluminum is $L = 3.97\times10^5 J/Kg$

mass to be malted m = 0.75 Kg

Energy require to melt E = mL

$E = 3.97\times10^5\times0.75 = 2.9775\times10^5 J$

Therefore, energy required to melt 0.75 Kg aluminum

$E = 2.9775\times10^5 J$

5 0

3 years ago

(a) If a proton with a kinetic energy of 6.2 MeV is traveling in a particle accelerator in a circular orbit with a radius of 0.5

Tju [1.3M]

Answer:

The fraction of its energy that it radiates every second is $3.02\times10^{-11}$ .

Explanation:

Suppose Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge that has charge q and acceleration a is given by

$\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}$

Given that,

Kinetic energy = 6.2 MeV

Radius = 0.500 m

We need to calculate the acceleration

Using formula of acceleration

$a=\dfrac{v^2}{r}$

Put the value into the formula

$a=\dfrac{\dfrac{1}{2}mv^2}{\dfrac{1}{2}mr}$

Put the value into the formula

$a=\dfrac{6.2\times10^{6}\times1.6\times10^{-19}}{\dfrac{1}{2}\times1.67\times10^{-27}\times0.51}$

$a=2.32\times10^{15}\ m/s^2$

We need to calculate the rate at which it emits energy because of its acceleration is

$\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}$

Put the value into the formula

$\dfrac{dE}{dt}=\dfrac{(1.6\times10^{-19})^2\times(2.3\times10^{15})^2}{6\pi\times8.85\times10^{-12}\times(3\times10^{8})^3}$

$\dfrac{dE}{dt}=3.00\times10^{-23}\ J/s$

The energy in ev/s

$\dfrac{dE}{dt}=\dfrac{3.00\times10^{-23}}{1.6\times10^{-19}}\ J/s$

$\dfrac{dE}{dt}=1.875\times10^{-4}\ ev/s$

We need to calculate the fraction of its energy that it radiates every second

$\dfrac{\dfrac{dE}{dt}}{E}=\dfrac{1.875\times10^{-4}}{6.2\times10^{6}}$

$\dfrac{\dfrac{dE}{dt}}{E}=3.02\times10^{-11}$

Hence, The fraction of its energy that it radiates every second is $3.02\times10^{-11}$ .

5 0

3 years ago

. Light travels at a speed of about 300 000 km/s. a. Express this value in scientific notation. b. Convert this value to meters

olganol [36]

Answer:

The answer to your question is below

Explanation:

Data

light speed = 300 000 km/s

a) Express it in scientific notation

to do it, we just move the decimal point 5 places to the left

300 000 = 3.0 x 10 ⁵ km/s

b) Convert this value to meters per hour

(300 000 km/s)(1000 m/1 km)(3600 s/1 h) = 300000x1000x3600 / 1x1x1

= 1.08 x 10¹² m/h

c) What distance in centimeters does light travel in 1 s?

data

v = 300 000 km/s

d = ?

t = 1 s

formula v = d/t we clear distance d = vxt

d = 300000 x 1 = 300000 km

d = 300000000 m = 30000000000 cm

4 0

3 years ago

You set a small eraser at a distance of 0.27 m from the center of a turntable you find in the attic and establish that when the

Licemer1 [7]

Answer with Explanation:

We are given that

Distance,r=0.27 m

Tangential speed=v=0.49 m/s

a.Angular speed , $\omega=\frac{v}{r}$

Using the formula

$\omega=\frac{0.49}{0.27}=1.8 rad/s$

$\omega=\frac{2\pi}{T}$

$T=\frac{2\pi}{\omega}$

Time period, $T=\frac{2\pi}{1.8}=3.49 s$

b.Amplitude,A=Distance of small eraser from the center of a turnable =0.27 m

c.Maximum speed, $V_{max}=0.49 m/s$

d.Maximum acceleration= $a=r\omega^2=0.27(1.8)^2=0.87 m/s^2$

5 0

3 years ago

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What is cocanve mirror?​

What is cocanve mirror?