This equation has no solution where 'a' and 'b'
are both non-zero real numbers.
You said 2a + 2b = 2a
Subtract 2a from each side: 2b = 0
'b' must be zero.
And it doesn't matter what the value of 'a' is.
As long as b=0, 'a' can be any number.
Answer:
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X-9=-13 because the 9 doesn't do with any of the others after the variable
Simplify the following:5 i/(3 i + 2)^2
(3 i + 2)^2 = 4 + 6 i + 6 i - 9 = -5 + 12 i:(5 i)/12 i - 5
Multiply numerator and denominator of (5 i)/(12 i - 5) by 5 + 12 i:(5 i (12 i + 5))/((12 i - 5) (12 i + 5))
(12 i - 5) (12 i + 5) = -5×5 - 5×12 i + 12 i×5 + 12 i×12 i = -25 - 60 i + 60 i - 144 = -169:(5 i (12 i + 5))/-169
i (12 i + 5) = -12 + 5 i:(5 5 i - 12)/(-169)
Multiply numerator and denominator of (5 (5 i - 12))/(-169) by -1:Answer: (-5 (5 i - 12))/169
(-5,-7) you always have to start with the x axis which will give you the x coordinate. The y axis gives you -7 the x gives -5. (x,y)
