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Zanzabum
3 years ago
6

10. Solve the system of equations 3y + 2z = 12 and y – z = 9. A. y = 6, z = –3 B. y = 24, z = 15 C. y = 6, z = 15 D. y = –6, z =

15
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0
3y + 2z = 12
Now you just try every answer until you get the right one.
A) y=6 z=-3
3×6 + 2×(-3) =18 -6=12
This is CORRECT
B) y=24 z=15
3×24 + 2×15= 72 + 30 =102
This is INCORRECT
C) y=6 z=15
3×6 + 2×15=18+30=48
This is INCORRECT
D)y=-6 z=15
3×(-6) + 2×15 = -18 + 30 = 12
This is CORRECT
So the correct answers are A and D
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Find the solutions of the system y = –2x – 1 and y = 3–x–1.
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There are two intersection points (-1, 1) and (-2, 3), and the x coordinates are -1 and -2.

<h3>What is an exponential function?</h3>

It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent y = a^x

where a is a constant and a>1

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have two equations:

y = –2x – 1 and

\rm y = 3^{-x-1}

From the graph, we can see:

There are two intersection points:

(-1, 1) and (-2, 3)

The x coordinates are -1 and -2

x = -1, y = 1

x = -2, y = 3

Thus, there are two intersection points (-1, 1) and (-2, 3), and the x coordinates are -1 and -2.

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5 0
2 years ago
The response to a question has three alternatives: A, B, and C. A sample of 120 responses provides 60 A, 12 B, and 48 C. Show th
zimovet [89]

Answer:

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

Step-by-step explanation:

Given that;

the frequencies of there alternatives are;

Frequency A = 60

Frequency B = 12

Frequency C = 48

Total = 60 + 12 + 48 = 120

Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;

Relative Frequency A = Frequency A / total = 60 / 120 = 0.5

Relative Frequency B = Frequency B / total = 12 / 120 = 0.1

Relative Frequency C = Frequency C / total = 48 / 120 = 0.4

therefore;

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

5 0
2 years ago
Can someone please help
Fynjy0 [20]

Answer:

angle C = 78

angle D = 108

Step-by-step explanation:

the measure of angle A is 102

To find the measure of angle C

let Angle C be x

102 + x = 180 (linear pair)

x = 180 -102

x = 78

angle C = 78

angle B = 78 (vertically opposite angles are equal)

angle D = 108 (vertically opposite angles are equal)

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3 years ago
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