The center of the circle is (0,2) and the radius is 5 units
<h3>How to determine the radius and the center?</h3>
The equation is given as:
x² + (y-2)² =25
The equation of a circle is given as:
(x - a)² + (y - b)² = r²
Where:
Center = (a,b)
Radius = r
By comparison, we have:
(a,b) = (0,2)
r² = 25
Evaluate
r = 5
Hence, the center of the circle is (0,2) and the radius is 5 units
Read more about circle equation at:
brainly.com/question/1559324
#SPJ1
Answer:
4.1 and 4.2
Step-by-step explanation:
or 4 and 5
Start at -4 and go to the right 6 times on the number line and you should end up with 2
Answer:
x=-2.5 if the function is
Step-by-step explanation:
has discontinuities when the denominator is 0.
You will either have a hole or a vertical asymptote depending on what happens to the numerator after you find when the bottom is 0.
That is whatever you found that makes the bottom 0, if it makes the top also 0 then you will have a hole at x=the number that made the bottom 0.
If it makes the top anything other than 0, then it is a vertical asymptote at x=the number you found that made the bottom 0.
Let's do this now.
When is -4x-10 equal to 0?
We have to solve the equation:
-4x-10=0
Add 10 on both sides:
-4x=10
Divide both sides by -4:
x=10/-4
Reduce by dividing top and bottom by 2:
x=5/-2
x=-5/2
or
x=-2.5 (if you want decimal form)
Now does it make the top 0? This is the deciding factor on whether you have a hole at x=-2.5 or a vertical asymptote at x=-2.5.
Let's see.
8(-2.5)-3=-23
Since the top is not 0 at x=-2.5 then you have a vertical asymptote at x=-2.5.
If the top were 0, then you would have had a hole at x=-2.5.