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Akimi4 [234]
3 years ago
15

1/6 of a gram of honey to make 1/10 of a pan of pudding. How many grams of honey r needed per pan of pudding?

Mathematics
2 answers:
kupik [55]3 years ago
7 0
Think:     1/6 gram honey  for   1/10 pan of pudding.  What if we mult. both sides by 10?

Then we have   10/6 gram honey for 10/10 (or 1) pan of pudding.  This rerduces to 5/3 gram of honey (answer)

You could also solve this by setting up and solving an equation of 2 ratios:

1/6          1/10
-----   =   ----------
  x            10/10
NISA [10]3 years ago
5 0
10/10 - 1 pan of pudding so 10 x 1/6 = 10/6 or 1 4/6 or 1 2/3 grams are needed
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Answer:

x=7, x=3

Step-by-step explanation:

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x^{2} -8x-2x+14+7=0

            x^{2} -10x+21=0

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x= \frac{-b\pm \sqrt{b^2-4ac}}{2a}

positive

x=\frac{-\left(-10\right)+\sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:21}}{2\cdot \:1}

x=7

negative

x=\frac{-\left(-10\right)-\sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:21}}{2\cdot \:1}

x=3

7 0
3 years ago
Choose the most appropriate strategy and then use it to solve the quadratic equation.
dsp73

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x1 = (1 + root (119) * i)) / 2
 
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