All categories

3 years ago

The measures of the angles of a triangle are shown in the figure below. Solve for x.

Mathematics

2 answers:

ryzh [129]3 years ago

5 0

(3x + 13) + (8x + 14) + 109 = 180°

(3x + 13) + (8x + 14) = 71°

11x + 27 = 71°

11x = 44°

x = 4

drek231 [11]3 years ago

5 0

Answer:

x = 4

(3x + 13) = 25°

(8x+ 14) = 46°

Step-by-step explanation:

(3x + 13) + (8x +14) + 109 = 180 (Angles of a triangle)

11x + 136 = 180

11x = 180 - 136

11x = 44

x = 4

Substituting the value of x

(3x + 13) = 3×4 + 13 = 12 + 13 = 25

(8x + 14) = 8×4 + 14 = 32 + 14 = 46

You might be interested in

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes?

So $n = 6, s = \frac{106}{\sqrt{6}} = 43.27$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 523}{43.27}$

$Z = -2.61$

$Z = -2.61$ has a pvalue of 0.0045.

So there is a 1-0.0045 = 0.9955 = 99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

6 0

3 years ago

AB formed by (-8, -1) and (-4, 2)<br> CD formed by (0, -3) and (12, 6)

marysya [2.9K]

Ah= 222jsjssksmzmsmsmms

5 0

3 years ago

Determine whether the following is an example of a sampling error or a non-sampling error. 12% of all people are left handed. A

const2013 [10]

Answer:

Sampling Error

Step-by-step explanation:

When the researcher randomly selected 200 people, he is creating an sample or subset from the population, that would be all the people in the earth. The error obtained was product of the fact that the analysis he made was estimated from the sample and not the whole population. There is no other mentioned factor that could cause an error, so the answer would be a sampling Error.

7 0

3 years ago

Max is observing the velocity of a runner at different times. After one hour, the velocity of the runner is 5 km/h. After two ho

Valentin [98]

You have velocity 1 of 5 km per hour after 1 hour and velocity 2 of 3 km per hour after 2 hours.

Part A)

Let Velocity = a +bt, with t being the time in hours.

For velocity 1 you have a +b = 5

For velocity 2, you have a + 2b =3

Now subtract velocity 1 from velocity 2:

a +2b - (a+b) = 3-5

Simplify to get b = -2

Now solve for a in the first equation:

a + b =5

Replace b with -2:

a - 2 = 5

a = 7

Now replace a and b in the original formula:

Velocity = 7 -2t

Part B)

Create a table with x and Y values to graph.

X axis would be the time and the velocity would be the Y axis

Your time would be 0 , 1, 2 3 and 4 hours.

Using the final equation from part A, replace t with the hours ans solve for the velocities, which become the y axis:

7 - 2(0) = 7-0 = 7

7 - 2(1) = 7-2 = 5

7 - 2(2) = 7-4 = 3

7 - 2(3) = 7-6 = 1

7-2(4) = 7-8 = -1

Now you have your x and y coordinates to plot on a graph:

(0,7) (1,5) (2,3) (3,1) and (4,-1)

7 0

3 years ago

Read 2 more answers

Hindle McKingleberry is a young child and has $3 in his bank account on the first day of the

matrenka [14]

Answer:you got this

Step-by-step explanation:

7 0

3 years ago