Question

A company that produces cranberries knows that about 7%7\%7%7, percent of its cranberries are bruised in the bagging process. They changed their bagging method, and they were curious if the proportion of cranberries bruised was different.
They tested H0:p=0.07H_0: p=0.07H0​:p=0.07H, start subscript, 0, end subscript, colon, p, equals, 0, point, 07 versus Ha:p≠0.07H_\text{a}:p\neq0.07Ha​:p​=0.07H, start subscript, start text, a, end text, end subscript, colon, p, does not equal, 0, point, 07, where pppp is the proportion of cranberries bruised, with a random sample of 600600600600 cranberries. They found that 10%10\%10%10, percent of cranberries in the sample were bruised. Those results yielded a test statistic of z≈2.88z \approx 2.88z≈2.88z, approximately equals, 2, point, 88 and a P-value of approximately 0.0040.0040.0040, point, 004. Assume that the conditions for inference were met.

Answer 1

Answer:

B. Yes, because 0.004<0.010.004<0.010, point, 004, is less than, 0, point, 01.

Step-by-step explanation:

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