Answer:
For example, LCM(2,3) = 6 and LCM(6,10) = 30.
At least 30 ..................
The equation that we can create from this situation is:
i = (190 – 5 x) * (29 + x)
where i is the income and x is the increase in daily rate
Expanding the equation:
i = 5510 + 190x – 145x - 5x^2
i = -5x^2 + 45x + 5510
Taking the 1st derivative:
di/dx = -10x +45
Set to zero to get the maxima:
-10x + 45 = 0
x = 4.5
So the cars should be rented at:
29 + x = 33.5 dollars per day
The maximum income is:
i = (190 – 5*4.5) * (33.5)
i = 5,611.25 dollars
Answer:
y = 1/3x - 19/3
Step-by-step explanation:
3y = x -3
y = 1/3x -3
Slope = 1/3
Point= (1,-6)
y-intercept = -6 - (1/3)(1) = -6 - 1/3 = -19/3
