Find a point-slope form for the line with slope 1/5 ( 1 over 5) and passing through the point (−8,−9)

Mathematics

1 answer:

leva [86]2 years ago

7 0

Answer:

y + 9 = 1/5(x + 8)

Step-by-step explanation:

Point-slope form: y - y₁ = m(x - x₁)

Substitute the values into the equation.

y - (-9) = 1/5(x - (-8)

y + 9 = 1/5(x + 8)

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Which are the solutions of x^2 = –11x + 4?

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This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

$x^2 + 11x - 4 = 0$

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

$x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}$

where $x_{1,2}$ is a compact way to indicate both solutions $x_1$ and $x_2$ , while $a,b,c$ are the coefficients of the quadratic equation, i.e. we consider the polynomial $ax^2+bx+c$ .

So, in your case, we have $a=1,\ \ b=11,\ \ c=-4$

Plug those values into the formula to get

$x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}$

So, the two solutions are

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