Franco:
3x+2y=19
Caryl:
2x+4y=24
now use elimination
-2(3x+2y=19)
1(2x+4y=24)
=
-6x-4y=-38
2x+4y=24
add them together
which equals -4x=-14
divide both sides by -4
-4x/-4=-14/-4
x=7/2
we found x, so we subsitute it into the the original equation
3x+2y=19
3(7/2)2y=19
2y+21/2=19
-21/2 -21/2
2y=17/2
divide by 2 on both sides
2y/2= 17/2/2
y=17/4
so x= 7/2 and y= 17/4
Check the picture below.
so the figure is really just 3 rectangles and two triangles.
simply get the area of all 5, sum them up, and that's the area of the figure.
recall that area of a triangle A = ½bh.
Answer:
22.29% probability that both of them scored above a 1520
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

The first step to solve the question is find the probability that a student has of scoring above 1520, which is 1 subtracted by the pvalue of Z when X = 1520.
So



has a pvalue of 0.5279
1 - 0.5279 = 0.4721
Each students has a 0.4721 probability of scoring above 1520.
What is the probability that both of them scored above a 1520?
Each students has a 0.4721 probability of scoring above 1520. So

22.29% probability that both of them scored above a 1520
The distnace around a two dimensional shape