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olasank [31]
3 years ago
9

How do you determine where f(x)=cos^(-1)(lnx) is continuous?

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
7 0
\ln x is continuous over its domain, all real x>0.

Meanwhile, \cos^{-1}y is defined for real -1\le y\le1.

If y=\ln x, then we have -1\le \ln x\le1\implies \dfrac1e\le x\le e as the domain of \cos^{-1}(\ln x).

We know that if f and g are continuous functions, then so is the composite function f\circ g.

Both \cos^{-1}y and \ln x are continuous on their domains (excluding the endpoints in the case of \cos^{-1}y), which means \cos^{-1}(\ln x) is continuous over \dfrac1e.
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Hope this helps!! :)

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