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3 years ago

11

I don't know how to solve this.

1 answer:

Leona [35]3 years ago

5 0

What is the question?

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Randy hung a total of 900 feet of Christmas lights on the exterior of his house this past holiday season. If 1 foot equals 30.48

bulgar [2K]

Answer:

900 divided by 30.48 =

Step-by-step explanation:

<u> 0 0. 0 3 3</u>

9 0 0 3 0. 4 8 0

− 0

3 0

<u> − 0 </u>

3 0 4

<u> − 0 </u>

3 0 4 8

<u> − 2 7 0 0 </u>

3 4 8 0

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Your answer is now many

Branlist plz

5 0

3 years ago

Read 2 more answers

A bike accelerates at 3m/s2. How fast will it be traveling after 8 seconds?

Likurg_2 [28]

Answer:5 x (25 + 125 )/ 2 = 750/2 m = 375 m.

Step-by-step explanation:

3 0

3 years ago

-2(4х + 4) — 3х – 2 = 34<br> Find x

djverab [1.8K]

Answer:

x = -4

Step-by-step explanation:

Distribute the -2 into the parentheses and your equation becomes -8x - 8 - 3x - 2 = 34

Then combine the -8x and -3x as well as the -8 and -2 to have -11x - 10 = 34

Add 10 to both sides and get -11x = 44

Divide both sides by -11 for x=-4

5 0

3 years ago

A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.

noname [10]

Answer:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

Step-by-step explanation:

Given

$Volume = 128ft^3$

$L = 2W$

$Base\ Cost = \$9/ft^2$

$Sides\ Cost = \$6/ft^2$

Required

The dimension that minimizes the cost

The volume is:

$Volume = LWH$

This gives:

$128 = LWH$

Substitute $L = 2W$

$128 = 2W * WH$

$128 = 2W^2H$

Make H the subject

$H = \frac{128}{2W^2}$

$H = \frac{64}{W^2}$

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

$A = LW + 2(WH + LH)$

The cost is:

$Cost = 9 * LW + 6 * 2(WH + LH)$

$Cost = 9 * LW + 12(WH + LH)$

$Cost = 9 * LW + 12H(W + L)$

Substitute: $H = \frac{64}{W^2}$ and $L = 2W$

$Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)$

$Cost =18W^2 + \frac{768}{W^2}*3W$

$Cost =18W^2 + \frac{2304}{W}$

To minimize the cost, we differentiate

$C' =2*18W + -1 * 2304W^{-2}$

Then set to 0

$2*18W + -1 * 2304W^{-2} =0$

$36W - 2304W^{-2} =0$

Rewrite as:

$36W = 2304W^{-2}$

Divide both sides by W

$36 = 2304W^{-3}$

Rewrite as:

$36 = \frac{2304}{W^3}$

Solve for $W^3$

$W^3 = \frac{2304}{36}$

$W^3 = 64$

Take cube roots

$W = 4$

Recall that:

$L = 2W$

$L = 2 * 4$

$L = 8$

$H = \frac{64}{W^2}$

$H = \frac{64}{4^2}$

$H = \frac{64}{16}$

$H = 4$

Hence, the dimension that minimizes the cost is:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

8 0

3 years ago

Write 2x - x2 = 1 in standard form.<br> An equation in standard form is

Marat540 [252]

Answer:

X^2-2X+1=0

Step-by-step explanation:

given,2X-X^2=1

or,-(X^2-2X)=1

or,X^2-2X=-1

or,X^2-2X+1=0 ,which is the req.equation in standard form.

6 0

3 years ago

Read 2 more answers