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3 years ago

26,250 over 100 simplified

Mathematics

1 answer:

balu736 [363]3 years ago

8 0

525/2 is the answer to your question. which may be a little bit of a larger fraction than normal

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Which statement about 5 multiplied by 1/8 must be true?

Kipish [7]

Answer:

The product is less than 1.

Step-by-step explanation:

Since $5\times \frac{1}{8} = \frac{5}{1}\times \frac{1}{8}=\frac{5}{8}$

and $\frac{5}{8}= 0.625$

which is less than 1, therefore we can say that the product is less than 1.

3 0

3 years ago

Which expression shows the sum of the polynomials with like terms grouped together? (8x+3z-8z^2)+(4y-5z)

Andrews [41]

It’s (-8z^2 +8x +4y -2z)

Hope it helps

3 0

3 years ago

Given that ABCD is a parallelogram, what must be proven to prove that the diagonals bisect each other?

Yuliya22 [10]

Answer:

We have to prove Δ ABO ≅ Δ CDO or, Δ DAO ≅ Δ BCO.

Step-by-step explanation:

Let us assume that ABCD is a parallelogram having diagonals AC and BD.

We have to prove that in a parallelogram the diagonals bisect each other.

Assume that the diagonals of ABCD i.e. AC and BD intersect at point O.

Therefore, to prove that the diagonals AC and BD bisect each other, we have to first prove that Δ ABO and Δ CDO are congruent or Δ DAO and Δ BCO are congruent.

In symbol, we have to prove Δ ABO ≅ Δ CDO or, Δ DAO ≅ Δ BCO. (Answer)

4 0

3 years ago

The amount of force one exerts on a wrench handle to loosen a bolt is inversely

Inessa [10]

Answer:

$F = \frac{1152}{l}$

b) l=19.2 units

Step-by-step explanation:

a)Let F represent the force and l represents the length of the wrench handle.

Then inverse variation relation is:

$F\propto \: \frac{1}{l}$

When we introduce the variation constant, we get:

$F = \: \frac{k}{l}$

From the question when F=96, l=12

$96= \: \frac{k}{12}$

$k = 1152$

The equation is

$F = \: \frac{1152}{l}$

b) If a person can only exert 60 pounds of force on a wrench,then

$60 = \frac{1152}{l}$

$\implies \: l = \frac{1152}{60}$

$l = 19.2$

Hence the length of the wrench must be 19.2 units

4 0

3 years ago

LAST ONE GUYSSS \small \angle L and \small \angle M are supplementary, \small m\angle L=12x+45 and \small m\angle M=18x-30. Dete

svp [43]

Answer:

$m\angle L = 111\degree \\m\angle M = 69\degree$

Step-by-step explanation:

Since, angle L and angle M are supplementary.

$\therefore m\angle L + m\angle M= 180\degree \\ \therefore \: 12x + 45 + 18x - 30 = 180 \degree \\ \therefore \: 30x + 15= 180 \degree\\ \therefore \: 30x= 180 \degree - 15 \degree\\ \therefore \: 30x= 165 \degree \\ x = \frac{165 \degree}{30} \\ x = 5.5 \degree \\ \\ m\angle L = 12x + 45 \\ m\angle L = 12 \times 5.5 + 45 \\ m\angle L = 66 + 45 \\ \huge \red{ \boxed{ m\angle L = 111 \degree}} \\ \\ m\angle M=18x - 30 \\ m\angle M=18 \times 5.5 - 30 \\ m\angle M=99 - 30 \\ \huge \purple{ \boxed{ m\angle M=69 \degree}} \\$

6 0

3 years ago