Question

Solve the system of linear equations by substitution. y = 2x + 8 y = -2x

Answer 1

Answer:

(- 2, 4 )

Step-by-step explanation:

y = 2x + 8 → (1)

y = - 2x → (2)

substitute y = 2x + 8 into (2)

2x + 8 = - 2x ( add 2x to both sides )

4x + 8 = 0 ( subtract 8 from both sides )

4x = - 8 ( divide both sides by 4 )

x = - 2

substitute x = - 2 into (2)

y = - 2(- 2) = 4

solution is (- 2, 4 )

Answer 2

Answer: $y=4,\:x=-2$

Step-by-step explanation:

$\begin{bmatrix}y=2x+8\\ y=-2x\end{bmatrix}$

$\mathrm{Substitute\:}y=-2x$

$\begin{bmatrix}-2x=2x+8\end{bmatrix}$

${Isolate\:}x{for -2x=2x+8$

$x=-2$

$\mathrm{For\:}y=-2x$

$\mathrm{Substitute\:}x=-2$

$y=-2\left(-2\right)$

$\mathrm{Simplify}$

$y=4$

$The\:solutions\:to\:the\:system\:of\:equations\:are:$

$y=4,\:x=-2$

Good Luck!