Answer:
A tree with a height of 6.2 ft is 3 standard deviations above the mean
Step-by-step explanation:
⇒ 
statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)
an X value is found Z standard deviations from the mean mu if:
In this case we have: 
We have four different values of X and we must calculate the Z-score for each
For X =5.4\ ft
Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.
⇒
statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean.
(FALSE)
For X =4.6 ft
Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean
.
⇒
statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean
(FALSE)
For X =5.8 ft
Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.
⇒
statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean.
(TRUE)
For X =6.2\ ft
Therefore, a tree with a height of 6.2 ft is 3 standard deviations above the mean.
646/3=x
To check it: x*3 should =646
Answer:
144
Step-by-step explanation:
First, do the top and bottom. The top is 2*4*3 or 24, and the bottom is 6*4 or 24.
Now, do the sides. It is a staircase that you can split into 6 2x2 blocks, or 6*4=24. Do the same with the other side to get 24 again.
Now for the front and back. This is 2*4*3 and 6*4 again, or 24 and 24.
Now you have 6 24's so just multiply these and get 144.
