WILL GIVE BRAINLIEST. NEED URGENTLY!

Draw the graph of y = 6 - 2x on the grid

igomit [66]

Answer:

See attached image for the requested graph

Step-by-step explanation:

The values completed in the table and text boxes as shown, are all correct.

For the plotting of the points and drawing of the line, please see the attached image.

8 0

3 years ago

4. Solve 5x - 7x + 6 = -2(x - 3) * (5 Points) (5 Points) 2 infinitely many solutions

mezya [45]

-2x + 6 = -2x + 6

this problem has infinite solutions :)

7 0

3 years ago

The circumference of the equator of a sphere was measured to be 82 82 cm with a possible error of 0.5 0.5 cm. Use linear approxi

True [87]

Answer:

The maximum error in the calculated surface area is approximately 8.3083 square centimeters.

Step-by-step explanation:

The circumference ( $s$ ), in centimeters, and the surface area ( $A_{s}$ ), in square centimeters, of a sphere are represented by following formulas:

$A_{s} = 4\pi\cdot r^{2}$ (1)

$s = 2\pi\cdot r$ (2)

Where $r$ is the radius of the sphere, in centimeters.

By applying (2) in (1), we derive this expression:

$A_{s} = 4\pi\cdot \left(\frac{s}{2\pi} \right)^{2}$

$A_{s} = \frac{s^{2}}{\pi^{2}}$ (3)

By definition of Total Differential, which is equivalent to definition of Linear Approximation in this case, we determine an expression for the maximum error in the calculated surface area ( $\Delta A_{s}$ ), in square centimeters:

$\Delta A_{s} = \frac{\partial A_{s}}{\partial s} \cdot \Delta s$

$\Delta A_{s} = \frac{2\cdot s\cdot \Delta s}{\pi^{2}}$ (4)

Where:

$s$ - Measure circumference, in centimeters.

$\Delta s$ - Possible error in circumference, in centimeters.

If we know that $s = 82\,cm$ and $\Delta s = 0.5\,cm$ , then the maximum error is:

$\Delta A_{s} \approx 8.3083\,cm^{2}$

The maximum error in the calculated surface area is approximately 8.3083 square centimeters.

6 0

3 years ago

Please find the answer to this function! F(2)= 6x^4-10x^3+40x-50

steposvetlana [31]

Answer-

$f(2)= 6x^4-10x^3+40x-50=46$

Solution-

The given function is,

$\Rightarrow f(x)= 6x^4-10x^3+40x-50$

Now, we have to find the value of f(x) at x=2 i.e f(2), so putting x as 2 in the given function,

$\Rightarrow f(2)= 6(2)^4-10(2)^3+40(2)-50$

$\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50$

$\Rightarrow f(2)= 96-80+80-50$

$\Rightarrow f(2)= 96-50$

$\Rightarrow f(2)= 46$

Therefore, f(2) was found to be 46.

7 0

3 years ago

a student walks 50m on a bearing 0.25 degrees and then 200m due east how far is she from her starting point.

Inessa05 [86]

Answer:

Step-by-step explanation:

I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):

** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.

** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.

** Due east has an angle measure of 0 degrees

Now let's begin.

We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:

$A_x=50cos(89.75)$ so