1/sin^2x-1/tan^2x=
1/sin^2x-1/ (sin^2x/cos^2x)<<sin tan= sin/cos>>
= 1/sin^2x- cos^2x / sin^2x
= (1- cos^2x) / sin^2x <<combining into a single fraction>>
sin^2 x / sin^2x <<since 1- cos^2 x sin^2 x
=1
this simplifies to 1.
<span>Cone Volume = (<span>π<span> • r² •<span> h) ÷ 3
</span></span></span></span>
<span>Cone Volume = (3.14 * 1.5^2 * 4.5) / 3
</span>Cone Volume = <span><span><span>10.5975
</span>
</span>
</span>
<span>
answer is B
</span>
(4h+2)(2h+8)
4htines 2h= 8h^2
4htimes8=32h
2 times 2h=4h
2 times 8=16
Add Middle two you have
8h^2+36h+16
Answer:
As a fraction it must be 1/3
