Answer:
Step-by-step explanation:
OS ≅ OU, so we will set those 2 expressions equal to each other and solve for y:
6y = 42 so
y = 7
Same goes for OT and OV:
x + 5 = 23 so
x = 18 and
SU = 84
1/6·30=5
so your answer is b)5
Answer:
11 meters
Step-by-step explanation:
Lets say that w = width of the rectangle, to start. If the length of the rectangle is 3 meters greater than 2 times the width, the length of the rectangle is equal to 3 + 2w.
The perimeter of the rectangle is 2 * length of rectangle + 2 * width of the rectangle. With the perimeter being equal to 30 and width being w and length being 2w+3:
The perimeter of the rectangle is 2(w) + 2(2w+3) = 30.
We first need to find out w first, which will give us the width of the rectangle. Taking it step by step, we get:
2w + 4w + 6 = 30
6w + 6= 30
6w = 24 which is done by subtracting both sides by 6 to put the variables on one side and the values on the other side
w = 4 which is done by dividing 6 on both sides
Ultimately, this gets width to be 4 meters. Now that we found the width, we need to plug w = 4 into the equation we set up for length which is 2w+3.
That being said, the ANSWER is:
length of rectangle = 2(4)+3 = 11 meters
Hope this helps! :)
The correct next step that Cynthia should do is to:
D. use the arc markings to determine the radius to
construct the circle
<span>The arc markings are actually used as the baseline in
determining the center and the radius of the circle. The arc markings are
created with the use of a compass. All other choices are completely irrelevant
because what we need is the arc and not the angles. The angles do not create
the circle. Letter C is also wrong because what we are trying to form is the
circle and not the triangle. The triangle is already created.</span>
Answer:
The mean score for all students on the quiz was 86.
Step-by-step explanation:
This question is solved by a weighed average.
To find the weighed average, we add the values multiplied by their weight, and after that we divide by the sum of weights.
In this problem, we have that:
Mr. Spears had 20 students in his class with a mean score of 80.
So 80 has a weight of 20.
Mrs. Guyton's class of 30 students had a mean score of 90.
So 90 has a weight of 30.
Overall, what was the mean score for all students on the quiz
The mean score for all students on the quiz was 86.
