1) The y- axis is where x = 0, so the line "y = -1/2x - 3" will cross the y-axis when x = 0. You plug in "x = 0" into the equation, and get y = 0 -3, so y = -3. That means the line " y = -1/2x - 3" will cross the y-axis ar (0, -3)
2) If there are 2 parallel lines, then there is no solution, because the definition of parallel lines is, " 2 lines in the same plane, that never meet." That makes the solution inconsistent.
Answer:
<h2 /><h2>
<em>answe</em><em>r</em><em> will</em><em> be</em><em> </em><em>0</em><em>.</em><em>3</em><em>5</em><em>3</em><em>8</em></h2>
Step-by-step explanation:
Answer:
Option C. 
Step-by-step explanation:
we know that
The probability of an event is the ratio of the size of the event space to the size of the sample space.
The size of the sample space is the total number of possible outcomes
The event space is the number of outcomes in the event you are interested in.
so
Let
x------> size of the event space (total person's hemoglobin level of 9 or above with age above 35 years)
y-----> size of the sample space (total person's age above 35 years)
so
In this problem we have
Complete the table to find the total person's hemoglobin level of 9 or above (person's age above 35)
Let
y------> total person's hemoglobin level between 9 and 11 (person's age above 35)
Find the value of x
substitute the values
Answer:
32.1% ( depending on question might have to round to 32% )
Step-by-step explanation:
60*52=3210
3210/100= 32.1
Answer: The correct answer is option C: Both events are equally likely to occur
Step-by-step explanation: For the first experiment, Corrine has a six-sided die, which means there is a total of six possible outcomes altogether. In her experiment, Corrine rolls a number greater than three. The number of events that satisfies this condition in her experiment are the numbers four, five and six (that is, 3 events). Hence the probability can be calculated as follows;
P(>3) = Number of required outcomes/Number of possible outcomes
P(>3) = 3/6
P(>3) = 1/2 or 0.5
Therefore the probability of rolling a number greater than three is 0.5 or 50%.
For the second experiment, Pablo notes heads on the first flip of a coin and then tails on the second flip. for a coin there are two outcomes in total, so the probability of the coin landing on a head is equal to the probability of the coin landing on a tail. Hence the probability can be calculated as follows;
P(Head) = Number of required outcomes/Number of all possible outcomes
P(Head) = 1/2
P(Head) = 0.5
Therefore the probability of landing on a head is 0.5 or 50%. (Note that the probability of landing on a tail is equally 0.5 or 50%)
From these results we can conclude that in both experiments , both events are equally likely to occur.
