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ivann1987 [24]
3 years ago
5

It's from the chapter : "exponents and powers"i need the workings tooplease help​

Mathematics
1 answer:
labwork [276]3 years ago
5 0

Answer:

505/19

Step-by-step explanation:

Easy

so [3^3-(1/2)^(-3)*(1/19)]

simplify

3^3-8/19

3^3=27

27-8/19

convert element to fraction

(27*19)/19-8/19

combine

(27*19-8)/19

505/19

Have a wonderful day ask me if you have more questions about MATH that goes for anyone who needs math help

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For any circle, which ratio is equal to the number n? Select all that apply. Plsss help me!!
barxatty [35]

Answer:

Options A-C-F

Step-by-step explanation:

we know that

<em>The circumference of a circle is equal to</em>

C=\pi D  or  C=2\pi r

where

D is the diameter and r is the radius

therefore

\pi =\frac{C}{D}  or \pi =\frac{C}{2r}

The number pi is the ratio circumference - diameter or is the ratio circumference - 2 times radius

<em>The area of the circle is equal to</em>

A=\pi r^{2}

therefore

The number pi is the ratio Area - radius squared

6 0
3 years ago
Identify a pattern and find the next number in the pattern.<br> -48, -24, -12, -6
vodka [1.7K]
It's would be plus haft that number (it's a negative) and the next number would be 0
3 0
3 years ago
Read 2 more answers
How do I do 8b(ii) ? Please help me thank you!
Mila [183]
Step One
======
Find the length of FO (see below)

All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)

Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ

Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.

FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)]                                           \
OJ = ??

[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2      Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2    Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2   Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )

Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.


7 0
3 years ago
Solve the following equation then place the correct number in the box provided. X/3 - 4 = 10
ivann1987 [24]
X = 42

x/3 - 4 = 10
+ 4 +4
x/3 = 14
•3 •3
x = 42
4 0
3 years ago
Find the volume of each pyramid. Round to the nearest tenth if necessary.
Alika [10]

Answer:

B.

Step-by-step explanation:

also if you wouldnt mind giving me brainliest, im just trying to rank up. only if u dont mind though.

5 0
3 years ago
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