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scoray [572]
4 years ago
7

Determine the equation for a line perpendicular to y=1/3+4 and has an x-intercept of 2.

Mathematics
2 answers:
Bumek [7]4 years ago
5 0

Answer:

y = -3x + 6

Step-by-step explanation:

Any line perpendicular to

y = (1/3)x + 4

has a slope of -1/(1/3) = -3

and equation

y = -3x + b  .................(1)

If the line has an x intercept of 2 at (0,2), then

0 = -3(2) + b

solving

b = 6

By substituting b=6 into (1), the line required

y = -3x + 6

nevsk [136]4 years ago
3 0

Answer:

y = -3x + 2

Step-by-step explanation:

y= \frac{1}{3}x +4

Slope m_{1}=\frac{1}{3}

slope of the perpendicular line m_{2} = \frac{-1}{m_{1}} = \frac{-1}{\frac{1}{3}}=-1*\frac{3}{1}=-3\\

b= 2

Slope intercept form of required line: y = mx + b

y = -3x + 2

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podryga [215]

Answer:

my brain says (c) or (b) so, my answer would be (C)

Step-by-step explanation:

6 0
4 years ago
2.5 x + 10 = x minus 0.5?
vovangra [49]

Answer: x = -7

Step-by-step explanation:

2.5x+10=x-0.5

Collect like terms

2.5x-x= -0.5 -10

1.5x= -10.5

X= -10.5/1.5

X= -7

7 0
3 years ago
Read 2 more answers
10. (a) Consider the following matrices: A = ( 2 ) B = (3) and C = (-3) w = Find the det(A). [1] (ii) Is the matrix A singular?
Viefleur [7K]

i) We have to find the determinant of A.

We can do this as:

\det(A)=|\begin{bmatrix}{3} & {6} \\ {1} & {-2}\end{bmatrix}|=3*(-2)-6*1=-6-6=-12

ii) We have to find if the matrix A is singular.

Singular matrix have determinant equal to 0.

This is not the case for A, as its determinant is -12. Then, A is not a singular matrix.

iii) We have to find the values of x and y so that AB = C.

We have to write the matrix multiplication and we will obtain a system of linear equations:

We can now solve the system of equations by adding 3 times the second equation to the first equation:

\begin{gathered} 3(x-2y)+(3x+6y)=3(-3)+(-3) \\ 3x-6y+3x+6y=-9-3 \\ 6x+0y=-12 \\ x=\frac{-12}{6} \\ x=-2 \end{gathered}

We can now use the second equation to find the value of y:

\begin{gathered} x-2y=-3 \\ x+3=2y \\ y=\frac{x+3}{2} \\ y=\frac{-2+3}{2} \\ y=\frac{1}{2} \end{gathered}

The values are x = -2 and y = 1/2.

iv) When we want to multiply two matrices, the required condition is that the number of columns of the matrix on the left is equal the number of rows of the matrix on the right.

In the case of A(2x2) and B(2x1), when we do A*B this condition is satisfied.

But when we try to multiply BA, the number of columns of B is not equal to the number of rows of A, so the matrix mulitplication is not possible.

Answer:

i) det(A) = -12

ii) A is not singular because singular matrices have determinant equal to zero.

iii) x = -2 and y = 1/2.

iv) Is not possible because the number of columns of the first matrix has to be equal to the number of rows of the second matrix.

6 0
1 year ago
Please help.<br> Algebra.
ladessa [460]
The answer is 1 bc the solution is (1,-3)
7 0
3 years ago
Oliver and Marie are graphing two equations on a coordinate grid. Oliver has graphed the equation y = 2x + 2. If Marie graphs y
Maslowich
It will be 5 down from Olivier's graph at -3 (Oliver's is at 2)
8 0
4 years ago
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