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poizon [28]
3 years ago
9

5. Statistical Literacy What terminology do we use for the probability of

Mathematics
1 answer:
ohaa [14]3 years ago
7 0

Answer:

The correct option is type I error.

Step-by-step explanation:

Consider the provided information.

Type I error is the error occur when we reject the true null hypothesis,

Type II error is the error occur when we fail to reject false null hypothesis.

Now consider the provided information.

The symbol do we use for  this probability is type I error.

Hence, the correct option is type I error.

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THE COST OF SALAD AT A RESTAURANT DEPENDS ON MANY FACTORS LIST AT LEAST TWO INDEPENDENT VARIABLES THAT COULD AFFECT THE COST OD
Contact [7]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
Aarti posted a comment on her blog. Each day the number of responses to her comment was 125% of the number she recieved on the p
Talja [164]

Answer:

125

Step-by-step explanation:

6 0
3 years ago
A flower shop received a total of 24 boxes of roses. Each box had red, yellow, and white roses. There were 16 roses in each box.
malfutka [58]
First, multiply 24 times 16 to give you a total amount of roses, 384. Second, subtract 125 red roses and 112 yellow roses to give you the amount of white roses. 384-125 (red) = 259. 259 - 112 (yellow) = 147. There are 147 white roses. 



3 0
3 years ago
Pls help me I'll give brainlest and points​
dmitriy555 [2]

Answer:

See below.

Step-by-step explanation:

a.

O is the origin, so its abscissa is 0. O: 0

The only point 4 units from O is A, so A: 4

Point C has a positive abscissa like A.

Points B and C have opposite abscissas. The only opposites are -3 and 3, but C is positive, and B is negative.

B: -3

C: 3

D: -4.5

E: -6

M = (4 + (-6))/2 = -1. M: -1

b.

OB = |0 - (-3)| = |3| = 3

DA = |-4.5 - 4| = |-8.5| = 8.5

4 0
3 years ago
Given: AB ≅ BC , m∠MOC = 135° OM − angle bisector of ∠AOB Prove: ∠ABO ≅ ∠CBO
Gennadij [26K]

Answer:

See explanation

Step-by-step explanation:

1. Angles AOM and MOC are supplementry angles. If m∠MOC = 135°, then

m∠AOM = 180° - 135° = 45°

2. OM − angle bisector of ∠AOB, then

m∠AOM = m∠MOB = 45°

3. Now

m∠BOC = m∠MOC - m∠MOB

m∠BOC = 135° - 45° = 90°

4. Since m∠BOC = 90°, BO is perpendicular to AC.

5. Consider isosceles triangle ABC (because AB ≅ BC). BO is the height drawn to the base, so it is an angle B bisector too, thus

∠ABO ≅ ∠CBO

8 0
3 years ago
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