1+4=5, 2+5=12, 3+6=21 , 8+11=? WHAT THE CORRECT ANSWER?/

Mathematics

1 answer:

Lorico [155]3 years ago

6 0

The answer is 40, take 21 from the last equation solved and add 8 to it then add 11

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The first term of a geometric sequence is –2 and the common ratio is -1/4. What are the next three terms of the sequence?

Gelneren [198K]

I agree with the answer being B because since it's a common ratio you could just multiply -1/4 with -2 and keep doing that with each new term

3 0

3 years ago

I really don’t understand this and just need an explanation of how to do it.

sertanlavr [38]

$\bf ~\hspace{12em}\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4
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\cfrac{2n}{-3n\cdot -2n^2}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{-2n^2}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{2n\cdot -n}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{2n}\cdot \cfrac{1}{-n}$

$\bf \cfrac{1}{-3n}\cdot \boxed{1}\cdot \cfrac{1}{-n}\implies \cfrac{1}{-3n\cdot -n}\implies \cfrac{1}{3n^2}
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\rule{34em}{0.25pt}\\\\
\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4\implies \left( \cfrac{1}{3n^2} \right)^4\implies \stackrel{\textit{distributing the exponent}}{\cfrac{1^4}{3^4n^{2\cdot 4}}}\implies \cfrac{1}{81n^8}$