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lapo4ka [179]
3 years ago
6

How do I find it out

Mathematics
1 answer:
Paraphin [41]3 years ago
4 0
The two equations are in the slope-intercept form, y = mx + b.

m is the slope and it is the rate of change.
b is the constant, and it is the initial value.

Eq. A: y = 3x + 4  ---> rate of change = m = 3; initial value = b = 4
Eq. B: y = 5x + 2  ---> rate of change = m = 5; initial value = b = 2

Now you can see which statement is true.

A. False
B. True
C. False
D. False
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T-7=19 what is the answer and how do you do it
jeka57 [31]
T=26
you just add 7 to the other side with 19 which gives you the answer
7 0
3 years ago
What is 31.415 rounded to the nearest cubic unit
tiny-mole [99]
I believe that is cubed. sense cubic unit is 3 and that has 3 numbers after the decimal point.
7 0
3 years ago
Find the Domain and Range of the graph<br> Plz helppppppppppp
Semenov [28]
Domain: 1 2 3 4 5 6 range: -1 0 1 2 3 6
3 0
3 years ago
Read 2 more answers
A 0. 0427 kg racquetball is moving 22. 3 m/s when it strikes a stationary box. The ball bounces back at 11. 5 m/s, while the box
andreyandreev [35.5K]

To solve the question we must know about the conservation of momentum.

<h2>Conservation of Momentum</h2>

According to the law of conservation of momentum, when two bodies collide with each other then their momentum is conserved if no external force acts on the system. therefore, the combined momentum of the two objects before collision will be equal to the combined momentum of the two objects after the collision.

the momentum of the two objects before the collision

                       = momentum of the two objects after the collision

The mass of the box is 0.30141 kg.

<h2>Explanation</h2>

Given to us

  • Mass of racquetball, m = 0.0427 kg,
  • Velocity of racquetball before Collision,  \bold{u_1} = 22.3 m/s,
  • Velocity of box before Collision,\bold{ u_2}  = 0 m/s,
  • Velocity of racquetball after Collision, \bold{v_1} = 11.5 m/s,
  • Velocity of box after Collision, \bold{v_2} = 1.53 m/s,

<h3>Assumption</h3>

Let the mass of the box be M.

<h3>Conservation Of Momentum</h3>

Momentum before collision = Momentum after collision

mu_1 + Mu_2 = mv_1 + Mv_2

given, the box was stationary before the collision,

mu_1 + Mu_2 = mv_1 + Mv_2\\\\&#10;mu_1 + 0 = mv_1 + Mv_2\\\\&#10;mu_1  - mv_1 = Mv_2\\\\&#10;M= \dfrac{mu_1  - mv_1}{v_2}

Substituting the values,

M= \dfrac{mu_1  - mv_1}{v_2}\\\\&#10;M = \dfrac{(0.0427 \times 22.3)  - (0.0427\times 11.5)}{1.53}\\\\&#10;M = 0.30141\ kg

Hence, the mass of the box is 0.30141 kg.

Learn more about Conservation of Momentum:

brainly.com/question/2141713

3 0
3 years ago
Replace the * by the smallest number so that 785* is divisible by 6​
pantera1 [17]

Answer:

780

Step-by-step explanation:

first we divide them

785/6=

remainder= 5

quotient =130

now we subtract the remainder as we wants the smallest number

785-5= 780

hope this helps you :)

4 0
3 years ago
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