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3 years ago

6

How do I find it out

1 answer:

Paraphin [41]3 years ago

4 0

The two equations are in the slope-intercept form, y = mx + b.

m is the slope and it is the rate of change.
b is the constant, and it is the initial value.

Eq. A: y = 3x + 4 ---> rate of change = m = 3; initial value = b = 4
Eq. B: y = 5x + 2 ---> rate of change = m = 5; initial value = b = 2

Now you can see which statement is true.

A. False
B. True
C. False
D. False

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FIRST ANSWER GET BRAINLEST

liraira [26]

Let's call x the price of a box of slime.

Gianna spent 4 × $58 for art supplies so 4(58) + 8x all together. We have

392 ≤ 4(58) + 8x ≤ 472

We can work with both inequalities at once. 4(58)=232 so we subtract that from all three sides.

160 ≤ 8x ≤ 240

Divide all three sides by 8, a positive number so the inequalities don't flip.

20 ≤ x ≤ 30

Answer: Least: $20, Most: $30

5 0

3 years ago

Read 2 more answers

If w = 9, x = 10, and y = 3, what does 6x over 5y equal?

nirvana33 [79]

Answer:

6x = 6 (10) => 60

5y = 5 (3) => 15

$\frac{6x}{5y} = > \frac{60}{15} = > 4$

hope that helps uhh!!

3 0

2 years ago

Read 2 more answers

Find the value of the variable.

Nikolay [14]

we are given that

both sides are equal

so, their length must be equal

$HK=\sqrt{(p-1)^2+(5-2)^2}$

$HK=\sqrt{(p-1)^2+9}$

now, we can find other side

$JK=\sqrt{(p-7)^2+(5-2)^2}$

$JK=\sqrt{(p-7)^2+9}$

now, we can set them equal

$HK=JK$

$\sqrt{(p-1)^2+9}=\sqrt{(p-7)^2+9}$

now, we can take square both sides

$(p-1)^2+9=(p-7)^2+9$

now, we can solve for p

$(p-1)^2=(p-7)^2$

$p^2-2p+1=p^2-14p+49$

$-2p+1=-14p+49$

$12p=48$

$p=4$ ..............Answer

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2 years ago

Spud's mom is going to make him a round birthday cake, and has asked for your help. Spud is a bit weird, and has already

joja [24]

Answer:

16 x 16 = 256

Step-by-step explanation:

So 256 might be the answer? this is confusing but are you on IXL?

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3 years ago

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Serhud [2]

Answer:

Hello how are you lol

Step-by-step explanation:

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2 years ago