It would take
for Carol to catch the sweet after Dave threw it.
Let

we want to calculate the value 
First, we have to calculate
using the formula

using
,
,
(the sweets are decelerating due to gravity!)

To calculate
, first calculate
, then
. Using the formula

and the values
,
,
(again, the sweets are decelerating to get to maximum height)

since, Carol is standing
above Dave, we have the relationship

so that

we can now calculate
;

taking
,
,
(the sweets are falling, so they are now accelerating)

So it would take

for Carol to catch the sweet after Dave threw it from the first floor.
Learn more here: brainly.com/question/84352