2 years ago

PLEASE ANSWER! 15 POINTS

Mathematics

1 answer:

Vikentia [17]2 years ago

4 0

Answer: 13/15

Step-by-step explanation:

1/5 + 2/3 = 13/15. Since 13/15 can’t be simplified, that’s your answer.

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Factor each expression 36abc +54ad

olya-2409 [2.1K]

Answer:

18a(2bc + 3d)

Step-by-step explanation:

36abc + 54ad

Step 1: Find the Highest Common Factor of each

36abc = 2×2×3×3×a×b×c = 18a × 2bc

54ad = 2×3×3×3×a×d = 18a × 3d

HCF = 2×3×3×a = 18a

Step 2: Factor out with HCF

18a(2bc + 3d)

7 0

3 years ago

Here jwu4444 thank u so much

Galina-37 [17]

Answer:

Step-by-step explanation:

8 0

3 years ago

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What’s the area and perimeter?

Angelina_Jolie [31]

Answer:

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Step-by-step explanation:

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4 0

2 years ago

Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$

Blizzard [7]

$\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}$

$a^{81}\equiv1^{81}\equiv1\pmod7$

$b^{91}\equiv2^{91}\pmod7$

$2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7$
$8\equiv1\pmod7$
$2\equiv2\pmod7$
$\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7$

$c^{27}\equiv6^{27}\pmod7$

$6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7$

$\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7$

6 0

3 years ago

Help please asappp!!!!!!!!!!!!!!!!!!

mario62 [17]

I think the answer is B! I hope that helps!!!!!

BRAINLY would be appreciated❤️

4 0

3 years ago