3 years ago

Find the 9th term of an arithmetic sequence that has a 4th term of 27 and a 5th term of 19

Mathematics

1 answer:

Harman [31]3 years ago

4 0

Answer:

-13

Step-by-step explanation:

5th term - 4th term = common difference

= 19 - 27

= -8

Thus the 9th term = 5th term + 4(-8)

= 19 - 32

= -13 (answer

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