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Kaylis [27]
3 years ago
13

Find the 9th term of an arithmetic sequence that has a 4th term of 27 and a 5th term of 19

Mathematics
1 answer:
Harman [31]3 years ago
4 0

Answer:

-13

Step-by-step explanation:

5th term - 4th term = common difference

= 19 - 27

= -8

Thus the 9th term =   5th term +  4(-8)

=  19 - 32

= -13  (answer

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7 0
3 years ago
Assessment started: undefined.
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Read 2 more answers
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