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Kaylis [27]
3 years ago
13

Find the 9th term of an arithmetic sequence that has a 4th term of 27 and a 5th term of 19

Mathematics
1 answer:
Harman [31]3 years ago
4 0

Answer:

-13

Step-by-step explanation:

5th term - 4th term = common difference

= 19 - 27

= -8

Thus the 9th term =   5th term +  4(-8)

=  19 - 32

= -13  (answer

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6 0
3 years ago
Solve the following exponential equation:<br><br>5^x=2 <br><br>e^x=10​
olya-2409 [2.1K]

Number 1.

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x=\frac{log(2)}{log(5)}, which then gives us that x=0.4306777777....

Number 2

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3 0
2 years ago
Which is the difference of 21 1/4 - 18 2/4<br> A 2 1/4 B 2 2/4 C 2 3/4 D 3 1/4
PSYCHO15rus [73]
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3 years ago
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Mamont248 [21]

Answer:

45.34

Step-by-step explanation:

you have to use the pythagorean theorem

4 0
3 years ago
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Olin [163]

Answer:

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Step-by-step explanation:

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hoped this helped!

Brainly, please?

4 0
3 years ago
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