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algol [13]
3 years ago
12

Models were build using a scale of 1 in : 50 ft. Find the height of the model for a building that is actually 470ft. tall.

Mathematics
1 answer:
velikii [3]3 years ago
5 0
Proportion: a:b = c:d where ad = bc

a = 1 ; b = 50 ; c = x ; d = 470

1 inches : 50 feet = x inches : 470 feet
1* 470 = 50x
470/50 = x
9.4 = x

The model should be 9.4 inches high.
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Rewrite the expression as a sum of terms, where each term is in the form k\cdot a^nk⋅a
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Answer:

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  =2a^{(\frac{1}{2}+2)}-4a^{(\frac{1}{2}-1)}\\\\=\boxed{2a^{\frac{5}{2}}-4a^{-\frac{1}{2}}}

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The relevant rules of exponents are ...

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You go to a steakhouse for dinner and the meal cost $10.35. If you have a coupon for 10% off your meal, what is the bill for din
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What is 8,663,943,526 rounded to the nearest hundred thousand?
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Use the diagram of the right triangle above and round your answer to the nearest hundredth.
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Option a: 17.32 \ {m} is the length of b

Explanation:

The angle of B is \angle B=60^{\circ} and a=10 \ m

We need to determine the length of b.

First, let us determine the angle of A.

Since, ABC is a triangle, then all the angles add up to 180°

Thus, we have,

\angle A+\angle B+\angle C=180^{\circ}

\angle A+60^{\circ}+90^{\circ}=180^{\circ}

       \angle A+150^{\circ}=180^{\circ}

                   \angle A=30^{\circ}

Thus, the angle of A is \angle A=30^{\circ}

Now, we shall determine the length of b using the sine law formula.

The formula for sine law is given by,

\frac{a}{\sin A}=\frac{b}{\sin B}

where a=10 \ m , \angle A=30^{\circ} , \angle B=60^{\circ}

Thus, we have,

\frac{10}{\sin 30}=\frac{b}{\sin 60}

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Multiplying both sides by 0.866, we get,

\frac{10\times0.866}{0.5}=b

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\frac{8.66}{0.5}=b

Dividing, we get,

17.32=b

Thus, the length of b is b=17.32 \ m

Hence, Option a is the correct answer.

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3 years ago
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