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wolverine [178]
3 years ago
5

An artist wants to reduce the size of a drawing using a scale factor of 3:1 . The original drawing has an area of 720 square inc

hes.
What is area of the new drawing?
Mathematics
1 answer:
Savatey [412]3 years ago
6 0

Answer:

The answer is 80

Step-by-step explanation:

We know that we have to reduce...so the answer has to be smaller than 720!

Because it's 720 inches squared, we must square our scale factor of 1/3 which equates to 1/9.

1/9 * 720 = 80.

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Find the distance between (-2,6) ,(4,8)
Yuri [45]

Answer:

\sqrt{40} OR 6.324555

Remember to round accordingly if not intended to be answered in square root form!

Step-by-step explanation:

Use the distance formula

5 0
3 years ago
What is the slope of the line <br><br> A. 0<br> B. 1<br> C. -4<br> D. Undefined
ohaa [14]

Answer:

undefined slope

Step-by-step explanation:

The line is a vertical line

Vertical lines have an undefined slope

3 0
3 years ago
Read 2 more answers
in a school gym, the ratio of the number of boys to the number of girls was 4:3 . after 160 boys left the gym, the ratio became
Annette [7]

Answer:

300 girls were there in the gym.

Step-by-step explanation:

Given:

The ratio of the number of boys to the number of girls was 4:3, after 160 boys left the gym, the ratio became 4:5.

Now, to find the number of girls in the gym.

The girls in the gym does not left, their quantity is same before and after.

So, we multiply the both ratios to make the girls ratio same:

4:3 × 5 = 20:15

4:5 × 3 = 12:15

Now, <em>we find the units of the ratio</em>.

<em>The ratio of boys dropped down by 160</em>:

20 - 12 = 8 units.

160 = 8 units

Now, dividing both sides by 8 we get:

20 = 1 unit

So, 1 unit = 20.

Now, girls = 15 units

So, 15 × 20 = 300.

Therefore, 300 girls were there in the gym.

3 0
4 years ago
We considered the differences between the temperature readings in January 1 of 1968 and 2008 at 51 locations in the continental
mr Goodwill [35]

Answer:

1.1-2.02\frac{4.9}{\sqrt{50}}=-0.30    

1.1+2.02\frac{4.9}{\sqrt{50}}=2.50    

So on this case the 90% confidence interval would be given by (-0.30;2.50)  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=1.1 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=4.9 represent the sample standard deviation

n=51 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=51-1=50

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,50)".And we see that t_{\alpha/2}=2.02

Now we have everything in order to replace into formula (1):

1.1-2.02\frac{4.9}{\sqrt{50}}=-0.30    

1.1+2.02\frac{4.9}{\sqrt{50}}=2.50    

So on this case the 90% confidence interval would be given by (-0.30;2.50)    

8 0
3 years ago
A fishbowl has a capacity of 192 fluid ounces. How many quarts is that?
DENIUS [597]

Answer:

hope this helps

Step-by-step explanation:

192 fl oz. = 6 quarts

to get this you divide the fluid ounces by 32.

7 0
3 years ago
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