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Otrada [13]
3 years ago
14

A hot-air balloon is moving on a bearing of 2450 at 31mph. A wind is blowing with the bearing of 2600 at 23mph. Find the compone

nt form of the velocity of the balloon.
Mathematics
2 answers:
mixer [17]3 years ago
8 0
 the awnser might be 150
Alborosie3 years ago
4 0

Answer:

V=(54i) \ mph

Step-by-step explanation:

According to the problem, the hot-air ballon and the wind are movind in the same direction, which means the component form of the velocity of the ballon is the net vector between both velocities.

Basically, the net velocity is

v_{net}=31 + 23 = 54 mph

Because both velocities have the same direction.

Assuming they are moving in a horizontal direction, the component of this velocity is

V=(54i) \ mph

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Consider quadrilateral ABCD. If diagonal AC bisects angles A and C, then ΔACB is congruent to ΔACD (ASA). Hence AB=AD and BC=CD (CPCTC).

Likewise, if diagonal BD bisects angles B and D, triangles BDA and BDC are congruent, thus AB=BC and AD=CD. (CPCTC again). Now, we have AB=BC=CD=AD, so the figure is a rhombus, hence a parallelogram.
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Sebastian wants to create a right triangle with side lengths 14 inches, 48 inches, and 5
allochka39001 [22]

Answer: Choice A

\text{Yes, because } 14^2+48^2 \text{ is equal to } 50^2

=======================================================

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The pythagorean theorem is a^2+b^2 = c^2

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The order of 'a' and b doesn't matter.

So a = 14, b = 48, c = 50

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Both sides result in 2500 which proves that 14^2+48^2 = 50^2 is a true statement. Therefore, we do have a right triangle.

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